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phi
 2 years ago
Best ResponseYou've already chosen the best response.0i^3 = i*i*i what is (i*i) ?

03453660
 2 years ago
Best ResponseYou've already chosen the best response.3you are learning thats great

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.0ohh!! I think I am starting to get it.. then could you try solving i120 to let me see?

phi
 2 years ago
Best ResponseYou've already chosen the best response.0I would first figure out what is i^4= i*i*i*i

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.0what about large numbers to simplify? I cant be doing square rootss of 1 all the time right?

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.0i^120?? i^99 for example..

03453660
 2 years ago
Best ResponseYou've already chosen the best response.3its very easy all you do is you have to remember some formulas i^2 = 1 , i^3 = 1 , and i^4 = 1

phi
 2 years ago
Best ResponseYou've already chosen the best response.0yes now if you wrote out i^120 it would be (i*i*i*i) * (i*i*i*i) * .... * (i*i*i*i)

phi
 2 years ago
Best ResponseYou've already chosen the best response.0how many groups of 4 i's are there?

03453660
 2 years ago
Best ResponseYou've already chosen the best response.3i^120 = (i^2)^60 = (1)^60 = 1

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.0how many groups of 4 i's? 30?

phi
 2 years ago
Best ResponseYou've already chosen the best response.0and 1 times itself 30 times is still 1

03453660
 2 years ago
Best ResponseYou've already chosen the best response.3no dont go for grouping method

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.0omg!! confused!! :'(( why there's maths on earth!! urgh!!

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.0why plus 0?? *got it from a website*

phi
 2 years ago
Best ResponseYou've already chosen the best response.0The first step to understanding this is to understand that you have 1*1*1*1*...*1 (30 times) if the problem were i^121 (one more i), it would be 1*1..*1 * i one i left over

phi
 2 years ago
Best ResponseYou've already chosen the best response.0once you get the idea, you can use the idea of exponents \[ i^{ab} = (i^a)^{b} \]

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.0ohh!! okay!! I think I am starting to understand.. omg!!

eeblue
 2 years ago
Best ResponseYou've already chosen the best response.003453660, could you try solving i^99?? I would like to see..

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.0what is the remainder when you divide 99 by 4?
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