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phiBest ResponseYou've already chosen the best response.0
i^3 = i*i*i what is (i*i) ?
 one year ago

03453660Best ResponseYou've already chosen the best response.3
dw:1350921834324:dw
 one year ago

03453660Best ResponseYou've already chosen the best response.3
dw:1350921921328:dw
 one year ago

03453660Best ResponseYou've already chosen the best response.3
you are learning thats great
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
ohh!! I think I am starting to get it.. then could you try solving i120 to let me see?
 one year ago

phiBest ResponseYou've already chosen the best response.0
I would first figure out what is i^4= i*i*i*i
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
what about large numbers to simplify? I cant be doing square rootss of 1 all the time right?
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
i^120?? i^99 for example..
 one year ago

03453660Best ResponseYou've already chosen the best response.3
its very easy all you do is you have to remember some formulas i^2 = 1 , i^3 = 1 , and i^4 = 1
 one year ago

phiBest ResponseYou've already chosen the best response.0
yes now if you wrote out i^120 it would be (i*i*i*i) * (i*i*i*i) * .... * (i*i*i*i)
 one year ago

phiBest ResponseYou've already chosen the best response.0
how many groups of 4 i's are there?
 one year ago

03453660Best ResponseYou've already chosen the best response.3
i^120 = (i^2)^60 = (1)^60 = 1
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
how many groups of 4 i's? 30?
 one year ago

phiBest ResponseYou've already chosen the best response.0
and 1 times itself 30 times is still 1
 one year ago

03453660Best ResponseYou've already chosen the best response.3
no dont go for grouping method
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
omg!! confused!! :'(( why there's maths on earth!! urgh!!
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
why plus 0?? *got it from a website*
 one year ago

phiBest ResponseYou've already chosen the best response.0
The first step to understanding this is to understand that you have 1*1*1*1*...*1 (30 times) if the problem were i^121 (one more i), it would be 1*1..*1 * i one i left over
 one year ago

03453660Best ResponseYou've already chosen the best response.3
dw:1350922786797:dw
 one year ago

phiBest ResponseYou've already chosen the best response.0
once you get the idea, you can use the idea of exponents \[ i^{ab} = (i^a)^{b} \]
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
ohh!! okay!! I think I am starting to understand.. omg!!
 one year ago

eeblueBest ResponseYou've already chosen the best response.0
03453660, could you try solving i^99?? I would like to see..
 one year ago

amistre64Best ResponseYou've already chosen the best response.0
what is the remainder when you divide 99 by 4?
 one year ago
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