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why is i3 equals to -i??

Mathematics
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|dw:1350921728993:dw|
isnt it?? :'(
no

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Other answers:

  • phi
i^3 = i*i*i what is (i*i) ?
|dw:1350921834324:dw|
|dw:1350921921328:dw|
omg!! I am so dumb..
you are learning thats great
ohh!! I think I am starting to get it.. then could you try solving i120 to let me see?
is this i^120???
  • phi
I would first figure out what is i^4= i*i*i*i
what about large numbers to simplify? I cant be doing square rootss of -1 all the time right?
i^120?? i^99 for example..
  • phi
what is i^4 ?
1?
its very easy all you do is you have to remember some formulas i^2 = -1 , i^3 = -1 , and i^4 = 1
  • phi
yes now if you wrote out i^120 it would be (i*i*i*i) * (i*i*i*i) * .... * (i*i*i*i)
  • phi
how many groups of 4 i's are there?
i^120 = (i^2)^60 = (-1)^60 = 1
how many groups of 4 i's? 30?
  • phi
and 1 times itself 30 times is still 1
no dont go for grouping method
omg!! confused!! :'(( why there's maths on earth!! urgh!!
|dw:1350922607696:dw|
why plus 0?? *got it from a website*
  • phi
The first step to understanding this is to understand that you have 1*1*1*1*...*1 (30 times) if the problem were i^121 (one more i), it would be 1*1..*1 * i one i left over
|dw:1350922786797:dw|
okay.. then??
  • phi
once you get the idea, you can use the idea of exponents \[ i^{ab} = (i^a)^{b} \]
ohh!! okay!! I think I am starting to understand.. omg!!
03453660, could you try solving i^99?? I would like to see..
|dw:1350923385923:dw|
lost :((
what is the remainder when you divide 99 by 4?

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