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eeblue

  • 2 years ago

why is i3 equals to -i??

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  1. eeblue
    • 2 years ago
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    |dw:1350921728993:dw|

  2. eeblue
    • 2 years ago
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    isnt it?? :'(

  3. 03453660
    • 2 years ago
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    no

  4. phi
    • 2 years ago
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    i^3 = i*i*i what is (i*i) ?

  5. 03453660
    • 2 years ago
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    |dw:1350921834324:dw|

  6. 03453660
    • 2 years ago
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    |dw:1350921921328:dw|

  7. eeblue
    • 2 years ago
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    omg!! I am so dumb..

  8. 03453660
    • 2 years ago
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    you are learning thats great

  9. eeblue
    • 2 years ago
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    ohh!! I think I am starting to get it.. then could you try solving i120 to let me see?

  10. 03453660
    • 2 years ago
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    is this i^120???

  11. phi
    • 2 years ago
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    I would first figure out what is i^4= i*i*i*i

  12. eeblue
    • 2 years ago
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    what about large numbers to simplify? I cant be doing square rootss of -1 all the time right?

  13. eeblue
    • 2 years ago
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    i^120?? i^99 for example..

  14. phi
    • 2 years ago
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    what is i^4 ?

  15. eeblue
    • 2 years ago
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    1?

  16. 03453660
    • 2 years ago
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    its very easy all you do is you have to remember some formulas i^2 = -1 , i^3 = -1 , and i^4 = 1

  17. phi
    • 2 years ago
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    yes now if you wrote out i^120 it would be (i*i*i*i) * (i*i*i*i) * .... * (i*i*i*i)

  18. phi
    • 2 years ago
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    how many groups of 4 i's are there?

  19. 03453660
    • 2 years ago
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    i^120 = (i^2)^60 = (-1)^60 = 1

  20. eeblue
    • 2 years ago
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    how many groups of 4 i's? 30?

  21. phi
    • 2 years ago
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    and 1 times itself 30 times is still 1

  22. 03453660
    • 2 years ago
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    no dont go for grouping method

  23. eeblue
    • 2 years ago
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    omg!! confused!! :'(( why there's maths on earth!! urgh!!

  24. eeblue
    • 2 years ago
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    |dw:1350922607696:dw|

  25. eeblue
    • 2 years ago
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    why plus 0?? *got it from a website*

  26. phi
    • 2 years ago
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    The first step to understanding this is to understand that you have 1*1*1*1*...*1 (30 times) if the problem were i^121 (one more i), it would be 1*1..*1 * i one i left over

  27. 03453660
    • 2 years ago
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    |dw:1350922786797:dw|

  28. eeblue
    • 2 years ago
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    okay.. then??

  29. phi
    • 2 years ago
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    once you get the idea, you can use the idea of exponents \[ i^{ab} = (i^a)^{b} \]

  30. eeblue
    • 2 years ago
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    ohh!! okay!! I think I am starting to understand.. omg!!

  31. eeblue
    • 2 years ago
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    03453660, could you try solving i^99?? I would like to see..

  32. eeblue
    • 2 years ago
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    |dw:1350923385923:dw|

  33. eeblue
    • 2 years ago
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    lost :((

  34. amistre64
    • 2 years ago
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    what is the remainder when you divide 99 by 4?

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