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Hi, could someone please explain the solution given to question 4 in here: https://docs.google.com/viewer?a=v&q=cache:hnmAe62b8gJ:www.bmoc.maths.org/home/ukmog2012solutions.pdf+&hl=en&gl=uk&pid=bl&srcid=ADGEESgwtd7UoCBq6FfZIQndvvDDehWFbBuqZ2Jr5FTX3OQQcIWjxGNz_lkvmRkBK_SXSBG2eusRoiWRdg8dPOFuTdOQ2VYG1q5XDO2Hj5YgqhkSe1y3404R0LazKRqjZXl9fda5MmY&sig=AHIEtbS5YjfAO6mxRl0UsvfZRtiUAsMUFw
I understand up until the point where it states the 6<ab
Thanks!
 one year ago
 one year ago
Hi, could someone please explain the solution given to question 4 in here: https://docs.google.com/viewer?a=v&q=cache:hnmAe62b8gJ:www.bmoc.maths.org/home/ukmog2012solutions.pdf+&hl=en&gl=uk&pid=bl&srcid=ADGEESgwtd7UoCBq6FfZIQndvvDDehWFbBuqZ2Jr5FTX3OQQcIWjxGNz_lkvmRkBK_SXSBG2eusRoiWRdg8dPOFuTdOQ2VYG1q5XDO2Hj5YgqhkSe1y3404R0LazKRqjZXl9fda5MmY&sig=AHIEtbS5YjfAO6mxRl0UsvfZRtiUAsMUFw I understand up until the point where it states the 6<ab Thanks!
 one year ago
 one year ago

This Question is Closed

CliffSedgeBest ResponseYou've already chosen the best response.1
2^6 = 64 and 641 = 63, a multiple of nine.
 one year ago

Rachel123Best ResponseYou've already chosen the best response.0
So is it done by just trying out numbers to show that it has to be greater than 6?
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Sortof, it's finding the least power of 2 that is 1 more than a multiple of 9. That shows that one number is at least that many powers of 2 greater than the other, so they can't possibly have the same number of digits.
 one year ago
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