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Rachel123
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Hi, could someone please explain the solution given to question 4 in here: https://docs.google.com/viewer?a=v&q=cache:hnmAe62b8gJ:www.bmoc.maths.org/home/ukmog2012solutions.pdf+&hl=en&gl=uk&pid=bl&srcid=ADGEESgwtd7UoCBq6FfZIQndvvDDehWFbBuqZ2Jr5FTX3OQQcIWjxGNz_lkvmRkBK_SXSBG2eusRoiWRdg8dPOFuTdOQ2VYG1q5XDO2Hj5YgqhkSe1y3404R0LazKRqjZXl9fda5MmY&sig=AHIEtbS5YjfAO6mxRl0UsvfZRtiUAsMUFw
I understand up until the point where it states the 6<ab
Thanks!
 2 years ago
 2 years ago
Rachel123 Group Title
Hi, could someone please explain the solution given to question 4 in here: https://docs.google.com/viewer?a=v&q=cache:hnmAe62b8gJ:www.bmoc.maths.org/home/ukmog2012solutions.pdf+&hl=en&gl=uk&pid=bl&srcid=ADGEESgwtd7UoCBq6FfZIQndvvDDehWFbBuqZ2Jr5FTX3OQQcIWjxGNz_lkvmRkBK_SXSBG2eusRoiWRdg8dPOFuTdOQ2VYG1q5XDO2Hj5YgqhkSe1y3404R0LazKRqjZXl9fda5MmY&sig=AHIEtbS5YjfAO6mxRl0UsvfZRtiUAsMUFw I understand up until the point where it states the 6<ab Thanks!
 2 years ago
 2 years ago

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CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
2^6 = 64 and 641 = 63, a multiple of nine.
 2 years ago

Rachel123 Group TitleBest ResponseYou've already chosen the best response.0
So is it done by just trying out numbers to show that it has to be greater than 6?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Sortof, it's finding the least power of 2 that is 1 more than a multiple of 9. That shows that one number is at least that many powers of 2 greater than the other, so they can't possibly have the same number of digits.
 2 years ago

Rachel123 Group TitleBest ResponseYou've already chosen the best response.0
Ok, great thanks!
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
yerwelcome
 2 years ago
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