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Rachel123
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Hi, could someone please explain the solution given to question 4 in here: https://docs.google.com/viewer?a=v&q=cache:hnmAe62b8gJ:www.bmoc.maths.org/home/ukmog2012solutions.pdf+&hl=en&gl=uk&pid=bl&srcid=ADGEESgwtd7UoCBq6FfZIQndvvDDehWFbBuqZ2Jr5FTX3OQQcIWjxGNz_lkvmRkBK_SXSBG2eusRoiWRdg8dPOFuTdOQ2VYG1q5XDO2Hj5YgqhkSe1y3404R0LazKRqjZXl9fda5MmY&sig=AHIEtbS5YjfAO6mxRl0UsvfZRtiUAsMUFw
I understand up until the point where it states the 6<ab
Thanks!
 one year ago
 one year ago
Rachel123 Group Title
Hi, could someone please explain the solution given to question 4 in here: https://docs.google.com/viewer?a=v&q=cache:hnmAe62b8gJ:www.bmoc.maths.org/home/ukmog2012solutions.pdf+&hl=en&gl=uk&pid=bl&srcid=ADGEESgwtd7UoCBq6FfZIQndvvDDehWFbBuqZ2Jr5FTX3OQQcIWjxGNz_lkvmRkBK_SXSBG2eusRoiWRdg8dPOFuTdOQ2VYG1q5XDO2Hj5YgqhkSe1y3404R0LazKRqjZXl9fda5MmY&sig=AHIEtbS5YjfAO6mxRl0UsvfZRtiUAsMUFw I understand up until the point where it states the 6<ab Thanks!
 one year ago
 one year ago

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CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
2^6 = 64 and 641 = 63, a multiple of nine.
 one year ago

Rachel123 Group TitleBest ResponseYou've already chosen the best response.0
So is it done by just trying out numbers to show that it has to be greater than 6?
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Sortof, it's finding the least power of 2 that is 1 more than a multiple of 9. That shows that one number is at least that many powers of 2 greater than the other, so they can't possibly have the same number of digits.
 one year ago

Rachel123 Group TitleBest ResponseYou've already chosen the best response.0
Ok, great thanks!
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
yerwelcome
 one year ago
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