A community for students. Sign up today!
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1site is not working for me idea is start by contradiction \[p=(\frac{a}{b})^n\] so \[b^np=a^n\] then note that all the primes in \(a^n\) how powers that are as multiple of \(n\) whereas on the left the power of \(p\) is not

henpen
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry for rebumping, the connection was so bad that it failed to notify me of your answer.

henpen
 2 years ago
Best ResponseYou've already chosen the best response.0Much more concise than other answers on sqrt2 proof thanks!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.