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henpen
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Prove that the nth root of a prime number is irrational, where n>1.
 one year ago
 one year ago
henpen Group Title
Prove that the nth root of a prime number is irrational, where n>1.
 one year ago
 one year ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.1
damn lost it
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
site is not working for me idea is start by contradiction \[p=(\frac{a}{b})^n\] so \[b^np=a^n\] then note that all the primes in \(a^n\) how powers that are as multiple of \(n\) whereas on the left the power of \(p\) is not
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
want more details?
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Sorry for rebumping, the connection was so bad that it failed to notify me of your answer.
 one year ago

henpen Group TitleBest ResponseYou've already chosen the best response.0
Much more concise than other answers on sqrt2 proof thanks!
 one year ago
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