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imron07
 2 years ago
Best ResponseYou've already chosen the best response.1Integrating by part will do, i think.

muntoo
 2 years ago
Best ResponseYou've already chosen the best response.0\[\large \int u \, dv=uv\int v \, du.\!\] Set \(u\) to something easily differentiable.

eexiam
 2 years ago
Best ResponseYou've already chosen the best response.0i got dw:1350949609547:dw

imron07
 2 years ago
Best ResponseYou've already chosen the best response.1\[u=x, du=dx\\dv=\ln(1+x)dx,v=\frac{1}{1+x}\\\int u\ dv=\frac{x}{1+x}\int \frac{1}{1+x}dx\]

imron07
 2 years ago
Best ResponseYou've already chosen the best response.1Finally,\[\int u \ dv=\frac{x}{1+x}\ln(1+x)+C\]

eexiam
 2 years ago
Best ResponseYou've already chosen the best response.0ohh ok that makes it easier then.
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