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imron07 Group TitleBest ResponseYou've already chosen the best response.1
Integrating by part will do, i think.
 2 years ago

muntoo Group TitleBest ResponseYou've already chosen the best response.0
\[\large \int u \, dv=uv\int v \, du.\!\] Set \(u\) to something easily differentiable.
 2 years ago

imron07 Group TitleBest ResponseYou've already chosen the best response.1
u=x dv=ln(1+x)
 2 years ago

eexiam Group TitleBest ResponseYou've already chosen the best response.0
i got dw:1350949609547:dw
 2 years ago

eexiam Group TitleBest ResponseYou've already chosen the best response.0
i think its wrong
 2 years ago

imron07 Group TitleBest ResponseYou've already chosen the best response.1
\[u=x, du=dx\\dv=\ln(1+x)dx,v=\frac{1}{1+x}\\\int u\ dv=\frac{x}{1+x}\int \frac{1}{1+x}dx\]
 2 years ago

imron07 Group TitleBest ResponseYou've already chosen the best response.1
Finally,\[\int u \ dv=\frac{x}{1+x}\ln(1+x)+C\]
 2 years ago

eexiam Group TitleBest ResponseYou've already chosen the best response.0
ohh ok that makes it easier then.
 2 years ago
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