anonymous
  • anonymous
i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
please i need help before tomorrow
anonymous
  • anonymous
where's the "figures" ???
anonymous
  • anonymous
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anonymous
  • anonymous
in the attachment below
anonymous
  • anonymous
do you see it
anonymous
  • anonymous
ok.. i see it.... that arrow way on the right is pointing north?
anonymous
  • anonymous
yes
anonymous
  • anonymous
to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees. so add those known angles then subtract the sum from 360 degrees ...
anonymous
  • anonymous
since the angles are given in degree-minute-seconds, give the measure of angle B the same way.
anonymous
  • anonymous
is angle b 360
anonymous
  • anonymous
no... angle B = 360 - (angle A + angle D + angle C)
anonymous
  • anonymous
121.483
anonymous
  • anonymous
sorry @krissywatts , i have to take off now... i'll page someone for you to get this problem continued.... @lgbasallote @helder_edwin @saifoo.khan @Hero bye... :) and, yes to your last post. i think might need to convert that decimal degrees to degree-minute-second... but i'm not sure....
anonymous
  • anonymous
saif!!! SIFU....
lgbasallote
  • lgbasallote
i'm doing some teacher stuff too...can't help... i'll page someone better than me though @dpaInc
anonymous
  • anonymous
okay
saifoo.khan
  • saifoo.khan
XD
anonymous
  • anonymous
what else do i need to do? for the other angles
saifoo.khan
  • saifoo.khan
If i'm not wrong, bearing of AB will be 84*21'
lgbasallote
  • lgbasallote
you're wrong though....too bad
helder_edwin
  • helder_edwin
\[ \large \angle B=121º29' \]
saifoo.khan
  • saifoo.khan
hold on a sec.
anonymous
  • anonymous
okay
saifoo.khan
  • saifoo.khan
I think it will be: 96º11' -84º21' = 11º50 Then: 180 - (11º50 +89º38) to get the bearing of AB
anonymous
  • anonymous
what about BC and DA?
helder_edwin
  • helder_edwin
the bearing of BC is N42º57'W
anonymous
  • anonymous
DA?
helder_edwin
  • helder_edwin
bearing of DA N11º50'W
helder_edwin
  • helder_edwin
bearing of AB E11º28'N
anonymous
  • anonymous
thanks
anonymous
  • anonymous
i chose you as best answer cause you stayed to help:)
helder_edwin
  • helder_edwin
u r welcome. and thank you the key is to draw a coordinate system on each point.
anonymous
  • anonymous
oh okay, yeah i didn't do that guess i should have
helder_edwin
  • helder_edwin
this theorem of geometry is key |dw:1350960824103:dw|
anonymous
  • anonymous
oh wait so angle be is 121.484 correct
anonymous
  • anonymous
B*
helder_edwin
  • helder_edwin
i posted the answer for that (my first post)
helder_edwin
  • helder_edwin
B=121º29'
anonymous
  • anonymous
okay
anonymous
  • anonymous
guess i didn't know because everyone was confused
helder_edwin
  • helder_edwin
ok. good luck.

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