krissywatts
i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?
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krissywatts
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please i need help before tomorrow
dpaInc
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where's the "figures" ???
krissywatts
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krissywatts
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in the attachment below
krissywatts
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do you see it
dpaInc
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ok.. i see it....
that arrow way on the right is pointing north?
krissywatts
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yes
dpaInc
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to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees.
so add those known angles then subtract the sum from 360 degrees ...
dpaInc
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since the angles are given in degree-minute-seconds, give the measure of angle B the same way.
krissywatts
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is angle b 360
dpaInc
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no...
angle B = 360 - (angle A + angle D + angle C)
krissywatts
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121.483
dpaInc
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sorry @krissywatts , i have to take off now...
i'll page someone for you to get this problem continued....
@lgbasallote
@helder_edwin
@saifoo.khan
@Hero
bye... :)
and, yes to your last post. i think might need to convert that decimal degrees to degree-minute-second... but i'm not sure....
dpaInc
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saif!!!
SIFU....
lgbasallote
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i'm doing some teacher stuff too...can't help... i'll page someone better than me though
@dpaInc
krissywatts
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okay
saifoo.khan
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XD
krissywatts
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what else do i need to do? for the other angles
saifoo.khan
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If i'm not wrong, bearing of AB will be 84*21'
lgbasallote
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you're wrong though....too bad
helder_edwin
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\[ \large \angle B=121º29' \]
saifoo.khan
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hold on a sec.
krissywatts
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okay
saifoo.khan
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I think it will be:
96º11' -84º21' = 11º50
Then: 180 - (11º50 +89º38)
to get the bearing of AB
krissywatts
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what about BC and DA?
helder_edwin
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the bearing of BC is N42º57'W
krissywatts
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DA?
helder_edwin
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bearing of DA N11º50'W
helder_edwin
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bearing of AB E11º28'N
krissywatts
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thanks
krissywatts
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i chose you as best answer cause you stayed to help:)
helder_edwin
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u r welcome. and thank you
the key is to draw a coordinate system on each point.
krissywatts
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oh okay, yeah i didn't do that guess i should have
helder_edwin
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this theorem of geometry is key
|dw:1350960824103:dw|
krissywatts
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oh wait so angle be is 121.484 correct
krissywatts
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B*
helder_edwin
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i posted the answer for that (my first post)
helder_edwin
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B=121º29'
krissywatts
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okay
krissywatts
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guess i didn't know because everyone was confused
helder_edwin
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ok. good luck.