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krissywatts
 3 years ago
i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?
krissywatts
 3 years ago
i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?

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krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0please i need help before tomorrow

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.2where's the "figures" ???

krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0in the attachment below

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.2ok.. i see it.... that arrow way on the right is pointing north?

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.2to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees. so add those known angles then subtract the sum from 360 degrees ...

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.2since the angles are given in degreeminuteseconds, give the measure of angle B the same way.

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.2no... angle B = 360  (angle A + angle D + angle C)

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.2sorry @krissywatts , i have to take off now... i'll page someone for you to get this problem continued.... @lgbasallote @helder_edwin @saifoo.khan @Hero bye... :) and, yes to your last post. i think might need to convert that decimal degrees to degreeminutesecond... but i'm not sure....

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0i'm doing some teacher stuff too...can't help... i'll page someone better than me though @dpaInc

krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0what else do i need to do? for the other angles

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0If i'm not wrong, bearing of AB will be 84*21'

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0you're wrong though....too bad

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1\[ \large \angle B=121º29' \]

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0I think it will be: 96º11' 84º21' = 11º50 Then: 180  (11º50 +89º38) to get the bearing of AB

krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0what about BC and DA?

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1the bearing of BC is N42º57'W

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1bearing of DA N11º50'W

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1bearing of AB E11º28'N

krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0i chose you as best answer cause you stayed to help:)

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1u r welcome. and thank you the key is to draw a coordinate system on each point.

krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay, yeah i didn't do that guess i should have

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1this theorem of geometry is key dw:1350960824103:dw

krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0oh wait so angle be is 121.484 correct

helder_edwin
 3 years ago
Best ResponseYou've already chosen the best response.1i posted the answer for that (my first post)

krissywatts
 3 years ago
Best ResponseYou've already chosen the best response.0guess i didn't know because everyone was confused
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