i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?

- anonymous

- schrodinger

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- anonymous

please i need help before tomorrow

- anonymous

where's the "figures" ???

- anonymous

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- anonymous

in the attachment below

- anonymous

do you see it

- anonymous

ok.. i see it....
that arrow way on the right is pointing north?

- anonymous

yes

- anonymous

to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees.
so add those known angles then subtract the sum from 360 degrees ...

- anonymous

since the angles are given in degree-minute-seconds, give the measure of angle B the same way.

- anonymous

is angle b 360

- anonymous

no...
angle B = 360 - (angle A + angle D + angle C)

- anonymous

121.483

- anonymous

sorry @krissywatts , i have to take off now...
i'll page someone for you to get this problem continued....
@lgbasallote
@helder_edwin
@saifoo.khan
@Hero
bye... :)
and, yes to your last post. i think might need to convert that decimal degrees to degree-minute-second... but i'm not sure....

- anonymous

saif!!!
SIFU....

- lgbasallote

i'm doing some teacher stuff too...can't help... i'll page someone better than me though
@dpaInc

- anonymous

okay

- saifoo.khan

XD

- anonymous

what else do i need to do? for the other angles

- saifoo.khan

If i'm not wrong, bearing of AB will be 84*21'

- lgbasallote

you're wrong though....too bad

- helder_edwin

\[ \large \angle B=121º29' \]

- saifoo.khan

hold on a sec.

- anonymous

okay

- saifoo.khan

I think it will be:
96º11' -84º21' = 11º50
Then: 180 - (11º50 +89º38)
to get the bearing of AB

- anonymous

what about BC and DA?

- helder_edwin

the bearing of BC is N42º57'W

- anonymous

DA?

- helder_edwin

bearing of DA N11º50'W

- helder_edwin

bearing of AB E11º28'N

- anonymous

thanks

- anonymous

i chose you as best answer cause you stayed to help:)

- helder_edwin

u r welcome. and thank you
the key is to draw a coordinate system on each point.

- anonymous

oh okay, yeah i didn't do that guess i should have

- helder_edwin

this theorem of geometry is key
|dw:1350960824103:dw|

- anonymous

oh wait so angle be is 121.484 correct

- anonymous

B*

- helder_edwin

i posted the answer for that (my first post)

- helder_edwin

B=121º29'

- anonymous

okay

- anonymous

guess i didn't know because everyone was confused

- helder_edwin

ok. good luck.

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