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i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?
 one year ago
 one year ago
i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?
 one year ago
 one year ago

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krissywattsBest ResponseYou've already chosen the best response.0
please i need help before tomorrow
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
where's the "figures" ???
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
in the attachment below
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
ok.. i see it.... that arrow way on the right is pointing north?
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees. so add those known angles then subtract the sum from 360 degrees ...
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
since the angles are given in degreeminuteseconds, give the measure of angle B the same way.
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
no... angle B = 360  (angle A + angle D + angle C)
 one year ago

dpaIncBest ResponseYou've already chosen the best response.2
sorry @krissywatts , i have to take off now... i'll page someone for you to get this problem continued.... @lgbasallote @helder_edwin @saifoo.khan @Hero bye... :) and, yes to your last post. i think might need to convert that decimal degrees to degreeminutesecond... but i'm not sure....
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i'm doing some teacher stuff too...can't help... i'll page someone better than me though @dpaInc
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
what else do i need to do? for the other angles
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.0
If i'm not wrong, bearing of AB will be 84*21'
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
you're wrong though....too bad
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
\[ \large \angle B=121º29' \]
 one year ago

saifoo.khanBest ResponseYou've already chosen the best response.0
I think it will be: 96º11' 84º21' = 11º50 Then: 180  (11º50 +89º38) to get the bearing of AB
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
what about BC and DA?
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
the bearing of BC is N42º57'W
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
bearing of DA N11º50'W
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
bearing of AB E11º28'N
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
i chose you as best answer cause you stayed to help:)
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
u r welcome. and thank you the key is to draw a coordinate system on each point.
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
oh okay, yeah i didn't do that guess i should have
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
this theorem of geometry is key dw:1350960824103:dw
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
oh wait so angle be is 121.484 correct
 one year ago

helder_edwinBest ResponseYou've already chosen the best response.1
i posted the answer for that (my first post)
 one year ago

krissywattsBest ResponseYou've already chosen the best response.0
guess i didn't know because everyone was confused
 one year ago
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