## krissywatts 3 years ago i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?

1. krissywatts

please i need help before tomorrow

2. dpaInc

where's the "figures" ???

3. krissywatts

4. krissywatts

in the attachment below

5. krissywatts

do you see it

6. dpaInc

ok.. i see it.... that arrow way on the right is pointing north?

7. krissywatts

yes

8. dpaInc

to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees. so add those known angles then subtract the sum from 360 degrees ...

9. dpaInc

since the angles are given in degree-minute-seconds, give the measure of angle B the same way.

10. krissywatts

is angle b 360

11. dpaInc

no... angle B = 360 - (angle A + angle D + angle C)

12. krissywatts

121.483

13. dpaInc

sorry @krissywatts , i have to take off now... i'll page someone for you to get this problem continued.... @lgbasallote @helder_edwin @saifoo.khan @Hero bye... :) and, yes to your last post. i think might need to convert that decimal degrees to degree-minute-second... but i'm not sure....

14. dpaInc

saif!!! SIFU....

15. lgbasallote

i'm doing some teacher stuff too...can't help... i'll page someone better than me though @dpaInc

16. krissywatts

okay

17. saifoo.khan

XD

18. krissywatts

what else do i need to do? for the other angles

19. saifoo.khan

If i'm not wrong, bearing of AB will be 84*21'

20. lgbasallote

you're wrong though....too bad

21. helder_edwin

\[ \large \angle B=121º29' \]

22. saifoo.khan

hold on a sec.

23. krissywatts

okay

24. saifoo.khan

I think it will be: 96º11' -84º21' = 11º50 Then: 180 - (11º50 +89º38) to get the bearing of AB

25. krissywatts

what about BC and DA?

26. helder_edwin

the bearing of BC is N42º57'W

27. krissywatts

DA?

28. helder_edwin

bearing of DA N11º50'W

29. helder_edwin

bearing of AB E11º28'N

30. krissywatts

thanks

31. krissywatts

i chose you as best answer cause you stayed to help:)

32. helder_edwin

u r welcome. and thank you the key is to draw a coordinate system on each point.

33. krissywatts

oh okay, yeah i didn't do that guess i should have

34. helder_edwin

this theorem of geometry is key |dw:1350960824103:dw|

35. krissywatts

oh wait so angle be is 121.484 correct

36. krissywatts

B*

37. helder_edwin

i posted the answer for that (my first post)

38. helder_edwin

B=121º29'

39. krissywatts

okay

40. krissywatts

guess i didn't know because everyone was confused

41. helder_edwin

ok. good luck.