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krissywatts

i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?

  • one year ago
  • one year ago

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  1. krissywatts
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    please i need help before tomorrow

    • one year ago
  2. dpaInc
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    where's the "figures" ???

    • one year ago
  3. krissywatts
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    • one year ago
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  4. krissywatts
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    in the attachment below

    • one year ago
  5. krissywatts
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    do you see it

    • one year ago
  6. dpaInc
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    ok.. i see it.... that arrow way on the right is pointing north?

    • one year ago
  7. krissywatts
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    yes

    • one year ago
  8. dpaInc
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    to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees. so add those known angles then subtract the sum from 360 degrees ...

    • one year ago
  9. dpaInc
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    since the angles are given in degree-minute-seconds, give the measure of angle B the same way.

    • one year ago
  10. krissywatts
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    is angle b 360

    • one year ago
  11. dpaInc
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    no... angle B = 360 - (angle A + angle D + angle C)

    • one year ago
  12. krissywatts
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    121.483

    • one year ago
  13. dpaInc
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    sorry @krissywatts , i have to take off now... i'll page someone for you to get this problem continued.... @lgbasallote @helder_edwin @saifoo.khan @Hero bye... :) and, yes to your last post. i think might need to convert that decimal degrees to degree-minute-second... but i'm not sure....

    • one year ago
  14. dpaInc
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    saif!!! SIFU....

    • one year ago
  15. lgbasallote
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    i'm doing some teacher stuff too...can't help... i'll page someone better than me though @dpaInc

    • one year ago
  16. krissywatts
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    okay

    • one year ago
  17. saifoo.khan
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    XD

    • one year ago
  18. krissywatts
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    what else do i need to do? for the other angles

    • one year ago
  19. saifoo.khan
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    If i'm not wrong, bearing of AB will be 84*21'

    • one year ago
  20. lgbasallote
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    you're wrong though....too bad

    • one year ago
  21. helder_edwin
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    \[ \large \angle B=121º29' \]

    • one year ago
  22. saifoo.khan
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    hold on a sec.

    • one year ago
  23. krissywatts
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    okay

    • one year ago
  24. saifoo.khan
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    I think it will be: 96º11' -84º21' = 11º50 Then: 180 - (11º50 +89º38) to get the bearing of AB

    • one year ago
  25. krissywatts
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    what about BC and DA?

    • one year ago
  26. helder_edwin
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    the bearing of BC is N42º57'W

    • one year ago
  27. krissywatts
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    DA?

    • one year ago
  28. helder_edwin
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    bearing of DA N11º50'W

    • one year ago
  29. helder_edwin
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    bearing of AB E11º28'N

    • one year ago
  30. krissywatts
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    thanks

    • one year ago
  31. krissywatts
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    i chose you as best answer cause you stayed to help:)

    • one year ago
  32. helder_edwin
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    u r welcome. and thank you the key is to draw a coordinate system on each point.

    • one year ago
  33. krissywatts
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    oh okay, yeah i didn't do that guess i should have

    • one year ago
  34. helder_edwin
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    this theorem of geometry is key |dw:1350960824103:dw|

    • one year ago
  35. krissywatts
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    oh wait so angle be is 121.484 correct

    • one year ago
  36. krissywatts
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    B*

    • one year ago
  37. helder_edwin
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    i posted the answer for that (my first post)

    • one year ago
  38. helder_edwin
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    B=121º29'

    • one year ago
  39. krissywatts
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    okay

    • one year ago
  40. krissywatts
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    guess i didn't know because everyone was confused

    • one year ago
  41. helder_edwin
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    ok. good luck.

    • one year ago
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