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krissywatts

  • 2 years ago

i need answers to these i have no clue how to get them? solve for the unknowns in figures A shown below: Angle B? Bearing of line AB? Bearing of line BC? Bearing of line DA?

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  1. krissywatts
    • 2 years ago
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    please i need help before tomorrow

  2. dpaInc
    • 2 years ago
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    where's the "figures" ???

  3. krissywatts
    • 2 years ago
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  4. krissywatts
    • 2 years ago
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    in the attachment below

  5. krissywatts
    • 2 years ago
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    do you see it

  6. dpaInc
    • 2 years ago
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    ok.. i see it.... that arrow way on the right is pointing north?

  7. krissywatts
    • 2 years ago
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    yes

  8. dpaInc
    • 2 years ago
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    to find angle B, notice that the sum of all the angles in any quadrilateral is 360 degrees. so add those known angles then subtract the sum from 360 degrees ...

  9. dpaInc
    • 2 years ago
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    since the angles are given in degree-minute-seconds, give the measure of angle B the same way.

  10. krissywatts
    • 2 years ago
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    is angle b 360

  11. dpaInc
    • 2 years ago
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    no... angle B = 360 - (angle A + angle D + angle C)

  12. krissywatts
    • 2 years ago
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    121.483

  13. dpaInc
    • 2 years ago
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    sorry @krissywatts , i have to take off now... i'll page someone for you to get this problem continued.... @lgbasallote @helder_edwin @saifoo.khan @Hero bye... :) and, yes to your last post. i think might need to convert that decimal degrees to degree-minute-second... but i'm not sure....

  14. dpaInc
    • 2 years ago
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    saif!!! SIFU....

  15. lgbasallote
    • 2 years ago
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    i'm doing some teacher stuff too...can't help... i'll page someone better than me though @dpaInc

  16. krissywatts
    • 2 years ago
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    okay

  17. saifoo.khan
    • 2 years ago
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    XD

  18. krissywatts
    • 2 years ago
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    what else do i need to do? for the other angles

  19. saifoo.khan
    • 2 years ago
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    If i'm not wrong, bearing of AB will be 84*21'

  20. lgbasallote
    • 2 years ago
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    you're wrong though....too bad

  21. helder_edwin
    • 2 years ago
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    \[ \large \angle B=121º29' \]

  22. saifoo.khan
    • 2 years ago
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    hold on a sec.

  23. krissywatts
    • 2 years ago
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    okay

  24. saifoo.khan
    • 2 years ago
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    I think it will be: 96º11' -84º21' = 11º50 Then: 180 - (11º50 +89º38) to get the bearing of AB

  25. krissywatts
    • 2 years ago
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    what about BC and DA?

  26. helder_edwin
    • 2 years ago
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    the bearing of BC is N42º57'W

  27. krissywatts
    • 2 years ago
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    DA?

  28. helder_edwin
    • 2 years ago
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    bearing of DA N11º50'W

  29. helder_edwin
    • 2 years ago
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    bearing of AB E11º28'N

  30. krissywatts
    • 2 years ago
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    thanks

  31. krissywatts
    • 2 years ago
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    i chose you as best answer cause you stayed to help:)

  32. helder_edwin
    • 2 years ago
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    u r welcome. and thank you the key is to draw a coordinate system on each point.

  33. krissywatts
    • 2 years ago
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    oh okay, yeah i didn't do that guess i should have

  34. helder_edwin
    • 2 years ago
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    this theorem of geometry is key |dw:1350960824103:dw|

  35. krissywatts
    • 2 years ago
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    oh wait so angle be is 121.484 correct

  36. krissywatts
    • 2 years ago
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    B*

  37. helder_edwin
    • 2 years ago
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    i posted the answer for that (my first post)

  38. helder_edwin
    • 2 years ago
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    B=121º29'

  39. krissywatts
    • 2 years ago
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    okay

  40. krissywatts
    • 2 years ago
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    guess i didn't know because everyone was confused

  41. helder_edwin
    • 2 years ago
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    ok. good luck.

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