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alainabbyboo22 Group Title

I am so confused on this .. can someone please help me out on how to solve the equation listed ? Find the value of x in the figure below. A. 1/4 B. 1 C. 4 D. 6

  • 2 years ago
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  1. alainabbyboo22 Group Title
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    • 2 years ago
  2. goformit100 Group Title
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    i got

    • 2 years ago
  3. alexandercpark Group Title
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    the radius of a circle will always hit a chord at a right angle, and always bisect the line this is all just a fancy way of saying though that \[3x+5=5x-7\]

    • 2 years ago
  4. alexandercpark Group Title
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    my geometry lingo is rusty but im confident that can lead you to the right answer

    • 2 years ago
  5. goformit100 Group Title
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    |dw:1350956332066:dw| do you agree with that you can use pythagoras' theorem here ??

    • 2 years ago
  6. goformit100 Group Title
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    |dw:1350956574279:dw|

    • 2 years ago
  7. goformit100 Group Title
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    in triangle ABC, reply how will you use pythgors' theorem

    • 2 years ago
  8. goformit100 Group Title
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    (OA)^2 = (OB)^2 + (BA)^2 OR, (OA)^2 = (OB)^2 + (5X-7)^2 ......... .......... ( 1 )

    • 2 years ago
  9. goformit100 Group Title
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    n triangle OBC, use pythgors' theorem

    • 2 years ago
  10. goformit100 Group Title
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    (OC)^2 = (OB)^2 + (BA)^2 OR, (OA)^2 = (OB)^2 + (3X+5)^2 ......... .......... ( 2 )

    • 2 years ago
  11. goformit100 Group Title
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    REPLY WHAT YOU GET WHEN YOU EQUATE BOTH EQUATIONS 1 AND 2 .....

    • 2 years ago
  12. goformit100 Group Title
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    @alainabbyboo22 REPLY

    • 2 years ago
  13. goformit100 Group Title
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    r you there ???

    • 2 years ago
  14. goformit100 Group Title
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    (3X+5)^2 = (5X-7)^2 Solve it for x ...

    • 2 years ago
  15. jhonyy9 Group Title
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    @goformit100 calcule you the x please ! good work nice

    • 2 years ago
  16. alainabbyboo22 Group Title
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    help !

    • 2 years ago
  17. alainabbyboo22 Group Title
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    could you please help me out with this ? i don't understand . @jhonyy9 help me ?

    • 2 years ago
  18. hba Group Title
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    Hint 1 >Apply Square root on both sides :)

    • 2 years ago
  19. jhonyy9 Group Title
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    (3x+5)^2 =(5x-7)^2 make squarroot on both sides 3x+5=5x-7 5+7=5x-3x 12=2x x=12/2 x=6

    • 2 years ago
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