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Jiimy20110 Group Title

Currently, Sam's coach is twice as old as Sam. When Sam started soccer 10 years ago, his coach was 3 times his age. How old is Sam now?

  • 2 years ago
  • 2 years ago

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  1. goformit100 Group Title
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    @satellite73

    • 2 years ago
  2. Jiimy20110 Group Title
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    help

    • 2 years ago
  3. Jiimy20110 Group Title
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    |dw:1350960568419:dw|

    • 2 years ago
  4. ChmE Group Title
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    50

    • 2 years ago
  5. ChmE Group Title
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    multiply 5 to both sides

    • 2 years ago
  6. Jiimy20110 Group Title
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    |dw:1350960670105:dw|

    • 2 years ago
  7. ChmE Group Title
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    c = 2s c-10 = 3(s-10) --> c - 10 = 3s - 30 --> c = 3s - 20 2s = 3s - 20 s = 20 c = 40 Wow that should not have been that hard for me. Sorry it took so long

    • 2 years ago
  8. Jiimy20110 Group Title
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    |dw:1350960915774:dw|

    • 2 years ago
  9. ChmE Group Title
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    Now he is twice sam's age. That is where the first equation came from. 10 years ago, so start with c - 10 and s - 10, the coach was 3 times sam's age. That is where the 3 comes from. I simplified then substituted in the 2s for c to solve for s. Then I knew c

    • 2 years ago
  10. Jiimy20110 Group Title
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    can you please solve the new problem on top

    • 2 years ago
  11. ChmE Group Title
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    y/-2 + 5 = 12 y/-2 + 5 - 5 = 12 - 5 y/-2 = 7 -2 * y/-2 = 7 * -2 y = -14

    • 2 years ago
  12. ChmE Group Title
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    \[x=\frac{ x-6 }{ 2 } =3\]\[2x=2\times \frac{ x-6 }{ 2 } =3 \times 2\]\[2x=x-6 =6\]Impossible, was there a typo in your original equation

    • 2 years ago
  13. Jiimy20110 Group Title
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    |dw:1350961540644:dw|

    • 2 years ago
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