anonymous
  • anonymous
x+1/5=x-1/2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Cancel x on both sides: 1/5 = -1/2. No solution.
anonymous
  • anonymous
These are proportions.. Im supposed to be using cross products.
anonymous
  • anonymous
I get a decimal... /:

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

goformit100
  • goformit100
ok
anonymous
  • anonymous
\[\Large \frac{x+1}{5}={x-1\over2}\] Be more specific next time. Use parenthesis or the equation editor.
anonymous
  • anonymous
Multiply both sides by \(5\cdot2\).
anonymous
  • anonymous
Ah, then you should have typed it like: (x+1)/5 = (x-1)/2. Careful with parentheses usage. So, when you cross-multiply (not cross product - that's a vector term), you get: \[ \dfrac {x+1}{5} = \dfrac {x-1}{2} \rightarrow 2(x+1) = 5(x-1) \rightarrow 2x + 2 = 5x - 5 \rightarrow 3x = -7, \] so you're right. It's a decimal. @goformit100 Spamming != Good. ;) @JessicaO Remember what muntoo and I said - be specific. ;)
goformit100
  • goformit100
i am not spamming
anonymous
  • anonymous
Thank y'all. :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.