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taydub10

  • 3 years ago

Sinx+tanx/1+secx

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  1. hartnn
    • 3 years ago
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    u need to simplify this ?

  2. hartnn
    • 3 years ago
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    write everything in terms of sin and cos u know tanx = ? sec x = ?

  3. taydub10
    • 3 years ago
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    Yes

  4. hartnn
    • 3 years ago
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    then put that in your expression, what u get ?

  5. taydub10
    • 3 years ago
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    Sin^x

  6. taydub10
    • 3 years ago
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    Sin^2x

  7. hartnn
    • 3 years ago
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    sin^2 x as final answer ? thats not correct. show your working....

  8. taydub10
    • 3 years ago
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    Sinx + sin/cos *cos/ q over 1/cos

  9. taydub10
    • 3 years ago
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    Please help

  10. klimenkov
    • 3 years ago
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    \(\sin x+\frac{\tan x}{1+\sec x}\)

  11. taydub10
    • 3 years ago
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    No sin x is also over the fraction

  12. klimenkov
    • 3 years ago
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    \(\frac{\sin x+\tan x}{1+\sec x}=\frac{\sin x+\frac{\sin x}{\cos x}}{1+\frac{1}{\cos x}}=\sin x\cdot\frac{1+\frac{1}{\cos x}}{1+\frac{1}{\cos x}}=\sin x\)

  13. taydub10
    • 3 years ago
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    So what's the final answer?

  14. taydub10
    • 3 years ago
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    What's the finalvanswer

  15. taydub10
    • 3 years ago
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    Is sinx the final answer

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