Here's the question you clicked on:
ihavemathquestions
Solve the system by substitution.
first equation can be rewritten as \(y=-2x-11\) substitute in to second equation get \[3x-4(-2x-11)=11\] \[3x+8x+44=11\] \[11x=-33\] \[x=-3\] and again you only have one choice so you do not need to find \(y\)
so is it (-5,-3) or (-3,-5)
we found \(x\) so it is \((-3,-5)\)