A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
A mass m1 = 5.3 kg rests on a frictionless table. It is connected by a massless and frictionless pulley to a second mass m2 = 3.2 kg that hangs freely.
1) What is the magnitude of the acceleration of block 1?
 2 years ago
A mass m1 = 5.3 kg rests on a frictionless table. It is connected by a massless and frictionless pulley to a second mass m2 = 3.2 kg that hangs freely. 1) What is the magnitude of the acceleration of block 1?

This Question is Closed

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.0@Nodata to the rescue! I know I should know this, but I'm still used to statics!

Mohamed7IBrahim
 2 years ago
Best ResponseYou've already chosen the best response.0you can use this Equation \[F \div M =m2g \div \left( m1+m2 \right)\]

brinethery
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you very much, I will try it out when I get home. I just spoke with my dad and he mentioned that you can do the sum of forces and solve for T. I'll try it both ways, thanks again.

Mohamed7IBrahim
 2 years ago
Best ResponseYou've already chosen the best response.0not at all be happy my friend

Nodata
 2 years ago
Best ResponseYou've already chosen the best response.1Espero que esto te sirva.

physics96help
 2 years ago
Best ResponseYou've already chosen the best response.0A ship is first seen on a radar screen to be 5 km east of the radar site. Some time later, the ship is at 17 km northwest. What is the displacement of the ship from the first location it is seen at?

alinaa
 2 years ago
Best ResponseYou've already chosen the best response.0(5.3*x)=(3.2*9.8) Find the value of x that will be the value of acceleration!
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.