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RodrigoAbrao
Power Series. Prove that sum (n/(n+1)!) = 1
\[\sum_{0}^{\infty} (n/(n+1)!)=1\]
\[\sum_{0}^{\infty}\frac{ n+1 }{ (n+1)! } -\sum_{0}^{\infty}\frac{ n }{ (n+1)! } = e - 1\]
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