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hiramoby
Group Title
Find all relative extrema of the function F(X)=16/(X^2+1). Use the SecondDerivative Test when applicable.
Answer
a.
The relative maximum is .1,0
b.
The relative minimum is .0,1
c.
The relative maximum is .0,16
d.
The relative minimum is .0,16
e.
The relative maximum is .16,0
 2 years ago
 2 years ago
hiramoby Group Title
Find all relative extrema of the function F(X)=16/(X^2+1). Use the SecondDerivative Test when applicable. Answer a. The relative maximum is .1,0 b. The relative minimum is .0,1 c. The relative maximum is .0,16 d. The relative minimum is .0,16 e. The relative maximum is .16,0
 2 years ago
 2 years ago

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Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
Take the derivative of this function first
 2 years ago

hiramoby Group TitleBest ResponseYou've already chosen the best response.1
here we go
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
First set f'(x) = 0 then solve for x, those will give you your critical points
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
also make sure to check the domain of f'(x) and the domain of f(x) if something is not in the domain of f'(x) but is in the domain of f(x) then it is a critical point if a point is not in the domain of f(x) but is in the domain of f'(x) then it is not a critical point
 2 years ago

hiramoby Group TitleBest ResponseYou've already chosen the best response.1
so it is going to be e then
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
ok make a table dw:1351050419295:dw
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
check in between these numbers and right if they are positive or negative
 2 years ago

hiramoby Group TitleBest ResponseYou've already chosen the best response.1
no b is the answer
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
you need to check to see if they are maximums or minimums
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
and I'm showing you how
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
Oh I made a mistake the table should be dw:1351050692097:dw so the general rule is 1. If f'(x) > 0 on the Interval than f(x) is increasing on the interval 2. If f'(x) < 0 on the Interval than f(x) is decreasing on the interval
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
So to show you an example of this 32x/(x^4 + 2x^2 + 1) sub in a number in the interval (infinity, 0) so I'm going with 1 32(1)/((1)^4 + 2(1)^2 + 1) = a positive number so we add in the table dw:1351050909010:dw
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
then we do it again for the next interval (0, 32) so I will pick 1 f'(1) = 32(1)/((1)^4 + 2(1)^2 + 1) = a negative number dw:1351051038432:dw so we see from this table that 0 is a maximum
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
I mean minimum
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
we can insert 0 into f(x) to see where this minimum is f(0) = 16/(X^2+1) f(0) = 16/1 f(0) = 16 so we have a minimum at (0,16)
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
I hope this was helpful :S
 2 years ago

Australopithecus Group TitleBest ResponseYou've already chosen the best response.0
oh crap made a mistake lol dw:1351051431080:dw it should be this you are right it is e maximum at (0,16)
 2 years ago
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