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Simplify. Use long division to solve. Subtract your answers, NOT add 10. (x^3 + 13x^2 - 12x - 8) / (x + 2)

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My answer is -72, but I don't know what to do next watch this video
Setup the long division as follows, solve by dividing . (x^3 + 13x^2 - 12x - 8) with (x + 2)
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Other answers:

it teaches you long division of polynomials
Check alternative forms to see if your answer is correct^3+%2B+13x^2+-+12x+-+8%29+%2F+%28x+%2B+2%29
what ever remainder you have left you have to keep it divided by x + 2
I know how to do it, it's just I don't know if I put it over x + 2 ----> \[\frac{ x + 2 }{ -72 }\]
What do you have for your long division?
x+2 remains in the denominator and it should be 60
I'm pretty sure based on wolfram alphas answer
@.Sam. so far
The answer goes with|dw:1351049782957:dw|
I know that; it's just I need help with where the -72 goes and @Australopithecus it's not 60
@Firejay5 the remainder is 60
No it's not it's -72 I did my work
Try check your work with this,
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It's -76
when you subtract; it's like you're distributing - into the second equation
Like when you are subtracting 11x^2 - 12x - (11x^2 + 22x)
you are are trying to cancel and get rid of the 11x^2
yes, then you get -34 x
It should be -34x - 8 - (34x + 68)
-34 x 2 = -68
its not +68 but its -68
what's -8 - 68
You should be careful there, its actually -8-(-68)
Are you getting confused??? @.Sam.
don't memorize the facts, just remember that it is top minus the bottom, you look back the previous steps, all you do is to subtract the top one with the bottom one, the steps that I gave you is computer generated, its completely true.
you have to apply the negative -(34x + 68) to all number s in parentheses
a remainder is just part of the equation that you cannot divide, so it is left with the denominator so in your case 60/(x+2)
The actual answer is 60, why are you ignoring it? Take a look at the picture below.
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I'm basing my 60/(x+2) on the wolfram alpha simplification
It's not -34x - 68 it's -(34x + 68) the minus/negative in front of the parentheses goes with everything in it

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