Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Assume that x and y are differentiable functions of t. A point is moving along the graph of the equation y=3x^2 -7x At what rate is y changing when x=8 and is changing at a rate of 3 units/sec? 2 hours ago - 4 days left to answer. Additional Details a. 144 units/sec b. 41 units/sec c. 51 units/sec d. 123 units/sec e. 27 units/sec

Differential Equations
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

-4 days left to answer? that's new...
So all you're doing here is differentiating with respect to t instead of x as normal. Think as though you're doing implicit differentiation! I'll go ahead and show you: \[\frac{ d }{ dt } (y)=\frac{ d }{ dt } (3x^2-7x)\] \[\frac{ dy }{ dt } =6x\frac{ dx }{ dt }-7\frac{ dx }{ dt } \] Now you're given dx/dt and x, just solve for dy/dt like the problem asks for algebraically! Problem solved.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question