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|dw:1351051208235:dw|

I'd start off with a free body diagram and sum of the forces

So do you know the x and y component of the force? Do you know how to get it?

i know that there is friction, gravity, and the Fsintheta. do you add all three together?

or subtract Fsintheta-(friction-gravity)

friction+gravity

@rachel_and u knw to Draw FBD

|dw:1351052476768:dw|

|dw:1351052525480:dw|

@rachel_and it shuld be Fsintheta-(friction+gravity)

Normal Reaction is a Contact Force...

So does F equal...
F(sin62-.497cos62) +2.48*9.8=0

|dw:1351053539218:dw|

Oh constant speed so no acceleration ! Sorry :P

I have the answer as 57.62 but apparently that is incorrect and I typed what @Algebraic! had

is your calc in degrees ?

Yes

so did you get it right?

make sure you multiply by the distance

yep. make sure it's not a sig. fig. or units error. pretty sure this answer is correct.

make sure you're supposed to be using 9.8 for g also.

No sig figs or units here. There's no chance that work is negative, right?

no F and displacement are both upwards.

sin62- .497cos62= .6496
2.48*9.8/ans=37.413
ans*1.54= 57.62

yep.

web assign?

mastering physics?

web assignment!

any chance you could screen shot the page and post it?

Is it the angle?

Should it be 28 instead ? 90 - 62?

Try 28 @rachel_and since it is 28 degrees with respect to the vertical

Locust grub needs help with his question too >:L

hmm not sure @rachel_and ...

D:<

Assignment deadline has past so I'll wait until the answers and solutions are posted. Thanks ya'll!!

don't forget to post back here with the right solution! :)

Will do!

ty!