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alainabbyboo22

  • 2 years ago

can someone help me please ? If AD = 8 cm and AC = 24.5 cm, calculate the length of AB. A. 16 cm B. 15 cm C. 30.63 cm D. 14 cm

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  1. alainabbyboo22
    • 2 years ago
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  2. alainabbyboo22
    • 2 years ago
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    do you know this ?

  3. jim_thompson5910
    • 2 years ago
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    hint: use theorem 3 on this page http://www.regentsprep.org/Regents/math/geometry/GP14/CircleSegments.htm

  4. waterineyes
    • 2 years ago
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    Liked it..

  5. alainabbyboo22
    • 2 years ago
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    i just still don't get this .

  6. waterineyes
    • 2 years ago
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    Theorem says : \[tangent^2 = Secant \cdot Chord\]

  7. waterineyes
    • 2 years ago
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    I.e : \[AB^2 = AD \cdot AC\] Just plug in the values..

  8. jim_thompson5910
    • 2 years ago
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    according to theorem 3 on that page b*c = a^2 In this context, if AB = x, AD = 8 and AC = 24.5, then (AD)*(AC) = (AB)^2 8*24.5 = x^2 Keep going to solve for x

  9. alainabbyboo22
    • 2 years ago
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    38416 . that is what i got cause i did 8*24.5 which equals 196 , then 196^2 and that gives me 38416 .

  10. jim_thompson5910
    • 2 years ago
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    you take the square root of 196

  11. jim_thompson5910
    • 2 years ago
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    this will give you a smaller number (than 196)

  12. alainabbyboo22
    • 2 years ago
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    14 !!

  13. alainabbyboo22
    • 2 years ago
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    thanks for helping me out on this (: i was lost !

  14. jim_thompson5910
    • 2 years ago
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    yw

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