anonymous
  • anonymous
can someone help me please ? If AD = 8 cm and AC = 24.5 cm, calculate the length of AB. A. 16 cm B. 15 cm C. 30.63 cm D. 14 cm
Geometry
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
do you know this ?
jim_thompson5910
  • jim_thompson5910
hint: use theorem 3 on this page http://www.regentsprep.org/Regents/math/geometry/GP14/CircleSegments.htm

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anonymous
  • anonymous
Liked it..
anonymous
  • anonymous
i just still don't get this .
anonymous
  • anonymous
Theorem says : \[tangent^2 = Secant \cdot Chord\]
anonymous
  • anonymous
I.e : \[AB^2 = AD \cdot AC\] Just plug in the values..
jim_thompson5910
  • jim_thompson5910
according to theorem 3 on that page b*c = a^2 In this context, if AB = x, AD = 8 and AC = 24.5, then (AD)*(AC) = (AB)^2 8*24.5 = x^2 Keep going to solve for x
anonymous
  • anonymous
38416 . that is what i got cause i did 8*24.5 which equals 196 , then 196^2 and that gives me 38416 .
jim_thompson5910
  • jim_thompson5910
you take the square root of 196
jim_thompson5910
  • jim_thompson5910
this will give you a smaller number (than 196)
anonymous
  • anonymous
14 !!
anonymous
  • anonymous
thanks for helping me out on this (: i was lost !
jim_thompson5910
  • jim_thompson5910
yw

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