Here's the question you clicked on:
alainabbyboo22
can someone help me please ? If AD = 8 cm and AC = 24.5 cm, calculate the length of AB. A. 16 cm B. 15 cm C. 30.63 cm D. 14 cm
do you know this ?
hint: use theorem 3 on this page http://www.regentsprep.org/Regents/math/geometry/GP14/CircleSegments.htm
i just still don't get this .
Theorem says : \[tangent^2 = Secant \cdot Chord\]
I.e : \[AB^2 = AD \cdot AC\] Just plug in the values..
according to theorem 3 on that page b*c = a^2 In this context, if AB = x, AD = 8 and AC = 24.5, then (AD)*(AC) = (AB)^2 8*24.5 = x^2 Keep going to solve for x
38416 . that is what i got cause i did 8*24.5 which equals 196 , then 196^2 and that gives me 38416 .
you take the square root of 196
this will give you a smaller number (than 196)
thanks for helping me out on this (: i was lost !