Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I need help with organic chem

Chemistry
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

can you please ask a question.
how to form hemiacetal/acetals
O H R1-C-H + O-R2 ------->

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Reaction of carbonyl groups with alcohol,
i need help getting what this means
1 Attachment
|dw:1351060446680:dw|
What type of file is that? Is that .doc, docx, .pdf, .txt?
not sure im on my mac
I can't open that, can you screenshot it?
|dw:1351060784194:dw|
this one was the aldehyde, alcohol and the last one is the hemiacetal
r u still there?
|dw:1351061659559:dw| Classify this monosaccharide as an aldose or a ketoses?
Its easy to look at it, that's aldose |dw:1351062443611:dw| There's no ketone group found in this molecule.
HOW ABOUT:.......
|dw:1351062552815:dw|
That's ketose because there's ketone group attached to it.
|dw:1351062770074:dw|
SO WHEN THE QUESTION IS ASKING CLASSIFY EACH OF THE FOLLOWING MONOSACCHARIDES AS AN ALDOSE OR A KETOSE ITS THAT SIMPLE?
|dw:1351062942152:dw| KETOSE?
An aldose is a monosaccharide that contains only one aldehyde (-CH=O) group in a molecule. As for ketose, a ketose is a sugar containing one ketone group in a molecule.
1 Attachment
@SoCalChris06 that's ketose.
|dw:1351063111146:dw| KETOSE?
ketose
SO ALL OF THEM WERE KETOSE BUT THE FIRST ONE?
yes
AND THE O THAT WAS ATTATCHED IS THE INDICATOR?
You do know that ketones are R-C(O)-R right?
And aldehydes are R-COH
YES
BUT WHAT DOES THE R MEAN
R groups are side chains, like Alchohol, Carbonyls (aldehydes and ketones), Carboxylic acid, Esters, Amines, Amides etc. Bonded to the molecule. We'll take ketone for example, |dw:1351063817237:dw| Take Carboxylic acid (-COOH) and Amines (-NH2) bonded with our ketone, it will look like this: |dw:1351063838534:dw|
OH, SO ITS LIKE THE N OR X IN ALGEBRA
THE UNKNOWN
Yes, R can be replaced by those
OH OK. I GOT IT
I HAVE ANOTHER QUESTION FROM MY BOOK:
THE INTERMOLECULAR REACTION THAT PRODUCES THE CYCLIC FORMS OF MONOSACCHARIDES INVOLVES FUNCTIONAL GROUPS ON WHICH 2 CARBON ATOMS IN THE CASE OF EACH OF THE FOLLOWING? A.) D-GLUCOSE B.)D-GALACTOSE C.)D-FRUCTOSE D.) D-RIBOSE
The only ketose group here is D-Fructose
IS THAT WHAT ITS ASKING?
Can you choose more than one?
I KNOW A IS ALPHA B IS ALPHA C IS BETA AND I DONT KNOW WHICH D IS
Its alpha , look: |dw:1351065817816:dw|
|dw:1351065913476:dw|
SO ITS ON OPPOSITE ENDS?
THE CH2OH AND OH, IS THAT WHAT YOURE LOOKING AT?
The Anomeric carbon be side the oxygen is always the one who determines whether its alpha or beta
WHAT DO U MEAN WHEN YOU SAY ANOMERIC
Take a look here: http://en.wikipedia.org/wiki/Anomer
1 Attachment
|dw:1351066163514:dw| SO, THE WAY I WAS ABLE TO DETERMINE IF IT WAS A ALPHA OR BETA CAUSE IF IT WAS ON THE OPPOSITE SIDE, (DIFFERENT) SIDES, ITS AN ALPHA. IF ITS ON THE SAME SIDE: |dw:1351066436831:dw|
SO, SAME SIDE IS BETA
THATS WHY THE LAST ONE THREW ME OFF
No, look closely its like this|dw:1351066676182:dw| You include the oxygen with the first carbon (or anomeric carbon), so for this one its beta.
ITS BETA CAUSE THE CH2OH AND OH ARE ON THE SAME SIDE RIGHT?
So, for the last one |dw:1351066852933:dw| is alpha
|dw:1351066888242:dw| CAUSE THEY ARE ON OPPOSITE SIDES?
|dw:1351066975972:dw| |dw:1351066986195:dw|
The -OH determines whether its a alpha or beta, when -OH is on top, its beta, when -OH is on bottom, its alpha
|dw:1351067070066:dw| SO WHY WHEN U SWITCHED THEM DID THEY CHANGE?
OHHHHHHHHHHHH!!!!!!!!!!!! LOL THAT MAKES SENSE...
WILL YOU BE ON HERE TOMORROW?
I NEED TO GET SOME REST. I NEED TO STUDY ALL DAY TOMORROW, BUT U HELPED ME WITH A FEW THINGS.
ITD BE COOL IF U CAN GET ON TOMORROW, AT ABOUT 8AM LOS ANGELES TIME.
Okay, I see whether if I'm free at that time.
YEA, ILL BE ON HERE BETWEN 8:30AM TO LIKE 2PM LOS ANGELES TIME
THANK YOU SO MUCH. I NEED TO PASS THIS TEST
Welcome ;)

Not the answer you are looking for?

Search for more explanations.

Ask your own question