anonymous
  • anonymous
I need help with organic chem
Chemistry
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
can you please ask a question.
anonymous
  • anonymous
how to form hemiacetal/acetals
anonymous
  • anonymous
O H R1-C-H + O-R2 ------->

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.Sam.
  • .Sam.
Reaction of carbonyl groups with alcohol,
anonymous
  • anonymous
i need help getting what this means
1 Attachment
.Sam.
  • .Sam.
|dw:1351060446680:dw|
.Sam.
  • .Sam.
What type of file is that? Is that .doc, docx, .pdf, .txt?
anonymous
  • anonymous
not sure im on my mac
.Sam.
  • .Sam.
I can't open that, can you screenshot it?
anonymous
  • anonymous
|dw:1351060784194:dw|
anonymous
  • anonymous
this one was the aldehyde, alcohol and the last one is the hemiacetal
anonymous
  • anonymous
r u still there?
anonymous
  • anonymous
|dw:1351061659559:dw| Classify this monosaccharide as an aldose or a ketoses?
.Sam.
  • .Sam.
Its easy to look at it, that's aldose |dw:1351062443611:dw| There's no ketone group found in this molecule.
anonymous
  • anonymous
HOW ABOUT:.......
anonymous
  • anonymous
|dw:1351062552815:dw|
.Sam.
  • .Sam.
That's ketose because there's ketone group attached to it.
.Sam.
  • .Sam.
|dw:1351062770074:dw|
anonymous
  • anonymous
SO WHEN THE QUESTION IS ASKING CLASSIFY EACH OF THE FOLLOWING MONOSACCHARIDES AS AN ALDOSE OR A KETOSE ITS THAT SIMPLE?
anonymous
  • anonymous
|dw:1351062942152:dw| KETOSE?
.Sam.
  • .Sam.
An aldose is a monosaccharide that contains only one aldehyde (-CH=O) group in a molecule. As for ketose, a ketose is a sugar containing one ketone group in a molecule.
1 Attachment
.Sam.
  • .Sam.
@SoCalChris06 that's ketose.
anonymous
  • anonymous
|dw:1351063111146:dw| KETOSE?
.Sam.
  • .Sam.
ketose
anonymous
  • anonymous
SO ALL OF THEM WERE KETOSE BUT THE FIRST ONE?
.Sam.
  • .Sam.
yes
anonymous
  • anonymous
AND THE O THAT WAS ATTATCHED IS THE INDICATOR?
.Sam.
  • .Sam.
You do know that ketones are R-C(O)-R right?
.Sam.
  • .Sam.
And aldehydes are R-COH
anonymous
  • anonymous
YES
anonymous
  • anonymous
BUT WHAT DOES THE R MEAN
.Sam.
  • .Sam.
R groups are side chains, like Alchohol, Carbonyls (aldehydes and ketones), Carboxylic acid, Esters, Amines, Amides etc. Bonded to the molecule. We'll take ketone for example, |dw:1351063817237:dw| Take Carboxylic acid (-COOH) and Amines (-NH2) bonded with our ketone, it will look like this: |dw:1351063838534:dw|
anonymous
  • anonymous
OH, SO ITS LIKE THE N OR X IN ALGEBRA
anonymous
  • anonymous
THE UNKNOWN
.Sam.
  • .Sam.
Yes, R can be replaced by those
anonymous
  • anonymous
OH OK. I GOT IT
anonymous
  • anonymous
I HAVE ANOTHER QUESTION FROM MY BOOK:
anonymous
  • anonymous
THE INTERMOLECULAR REACTION THAT PRODUCES THE CYCLIC FORMS OF MONOSACCHARIDES INVOLVES FUNCTIONAL GROUPS ON WHICH 2 CARBON ATOMS IN THE CASE OF EACH OF THE FOLLOWING? A.) D-GLUCOSE B.)D-GALACTOSE C.)D-FRUCTOSE D.) D-RIBOSE
.Sam.
  • .Sam.
The only ketose group here is D-Fructose
anonymous
  • anonymous
IS THAT WHAT ITS ASKING?
.Sam.
  • .Sam.
Can you choose more than one?
anonymous
  • anonymous
anonymous
  • anonymous
I KNOW A IS ALPHA B IS ALPHA C IS BETA AND I DONT KNOW WHICH D IS
.Sam.
  • .Sam.
Its alpha , look: |dw:1351065817816:dw|
.Sam.
  • .Sam.
|dw:1351065913476:dw|
anonymous
  • anonymous
SO ITS ON OPPOSITE ENDS?
anonymous
  • anonymous
THE CH2OH AND OH, IS THAT WHAT YOURE LOOKING AT?
.Sam.
  • .Sam.
The Anomeric carbon be side the oxygen is always the one who determines whether its alpha or beta
anonymous
  • anonymous
WHAT DO U MEAN WHEN YOU SAY ANOMERIC
.Sam.
  • .Sam.
Take a look here: http://en.wikipedia.org/wiki/Anomer
.Sam.
  • .Sam.
1 Attachment
anonymous
  • anonymous
|dw:1351066163514:dw| SO, THE WAY I WAS ABLE TO DETERMINE IF IT WAS A ALPHA OR BETA CAUSE IF IT WAS ON THE OPPOSITE SIDE, (DIFFERENT) SIDES, ITS AN ALPHA. IF ITS ON THE SAME SIDE: |dw:1351066436831:dw|
anonymous
  • anonymous
SO, SAME SIDE IS BETA
anonymous
  • anonymous
THATS WHY THE LAST ONE THREW ME OFF
.Sam.
  • .Sam.
No, look closely its like this|dw:1351066676182:dw| You include the oxygen with the first carbon (or anomeric carbon), so for this one its beta.
anonymous
  • anonymous
ITS BETA CAUSE THE CH2OH AND OH ARE ON THE SAME SIDE RIGHT?
.Sam.
  • .Sam.
So, for the last one |dw:1351066852933:dw| is alpha
anonymous
  • anonymous
|dw:1351066888242:dw| CAUSE THEY ARE ON OPPOSITE SIDES?
.Sam.
  • .Sam.
|dw:1351066975972:dw| |dw:1351066986195:dw|
.Sam.
  • .Sam.
The -OH determines whether its a alpha or beta, when -OH is on top, its beta, when -OH is on bottom, its alpha
anonymous
  • anonymous
|dw:1351067070066:dw| SO WHY WHEN U SWITCHED THEM DID THEY CHANGE?
anonymous
  • anonymous
OHHHHHHHHHHHH!!!!!!!!!!!! LOL THAT MAKES SENSE...
anonymous
  • anonymous
WILL YOU BE ON HERE TOMORROW?
anonymous
  • anonymous
I NEED TO GET SOME REST. I NEED TO STUDY ALL DAY TOMORROW, BUT U HELPED ME WITH A FEW THINGS.
anonymous
  • anonymous
ITD BE COOL IF U CAN GET ON TOMORROW, AT ABOUT 8AM LOS ANGELES TIME.
.Sam.
  • .Sam.
Okay, I see whether if I'm free at that time.
anonymous
  • anonymous
YEA, ILL BE ON HERE BETWEN 8:30AM TO LIKE 2PM LOS ANGELES TIME
anonymous
  • anonymous
THANK YOU SO MUCH. I NEED TO PASS THIS TEST
.Sam.
  • .Sam.
Welcome ;)

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