A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
I need help with organic chem
anonymous
 4 years ago
I need help with organic chem

This Question is Open

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you please ask a question.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how to form hemiacetal/acetals

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0O H R1CH + OR2 >

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2Reaction of carbonyl groups with alcohol,

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i need help getting what this means

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2What type of file is that? Is that .doc, docx, .pdf, .txt?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0not sure im on my mac

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2I can't open that, can you screenshot it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351060784194:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0this one was the aldehyde, alcohol and the last one is the hemiacetal

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351061659559:dw Classify this monosaccharide as an aldose or a ketoses?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2Its easy to look at it, that's aldose dw:1351062443611:dw There's no ketone group found in this molecule.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351062552815:dw

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2That's ketose because there's ketone group attached to it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SO WHEN THE QUESTION IS ASKING CLASSIFY EACH OF THE FOLLOWING MONOSACCHARIDES AS AN ALDOSE OR A KETOSE ITS THAT SIMPLE?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351062942152:dw KETOSE?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2An aldose is a monosaccharide that contains only one aldehyde (CH=O) group in a molecule. As for ketose, a ketose is a sugar containing one ketone group in a molecule.

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2@SoCalChris06 that's ketose.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351063111146:dw KETOSE?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SO ALL OF THEM WERE KETOSE BUT THE FIRST ONE?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0AND THE O THAT WAS ATTATCHED IS THE INDICATOR?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2You do know that ketones are RC(O)R right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0BUT WHAT DOES THE R MEAN

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2R groups are side chains, like Alchohol, Carbonyls (aldehydes and ketones), Carboxylic acid, Esters, Amines, Amides etc. Bonded to the molecule. We'll take ketone for example, dw:1351063817237:dw Take Carboxylic acid (COOH) and Amines (NH2) bonded with our ketone, it will look like this: dw:1351063838534:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OH, SO ITS LIKE THE N OR X IN ALGEBRA

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2Yes, R can be replaced by those

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I HAVE ANOTHER QUESTION FROM MY BOOK:

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0THE INTERMOLECULAR REACTION THAT PRODUCES THE CYCLIC FORMS OF MONOSACCHARIDES INVOLVES FUNCTIONAL GROUPS ON WHICH 2 CARBON ATOMS IN THE CASE OF EACH OF THE FOLLOWING? A.) DGLUCOSE B.)DGALACTOSE C.)DFRUCTOSE D.) DRIBOSE

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2The only ketose group here is DFructose

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0IS THAT WHAT ITS ASKING?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2Can you choose more than one?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I KNOW A IS ALPHA B IS ALPHA C IS BETA AND I DONT KNOW WHICH D IS

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2Its alpha , look: dw:1351065817816:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SO ITS ON OPPOSITE ENDS?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0THE CH2OH AND OH, IS THAT WHAT YOURE LOOKING AT?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2The Anomeric carbon be side the oxygen is always the one who determines whether its alpha or beta

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0WHAT DO U MEAN WHEN YOU SAY ANOMERIC

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2Take a look here: http://en.wikipedia.org/wiki/Anomer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351066163514:dw SO, THE WAY I WAS ABLE TO DETERMINE IF IT WAS A ALPHA OR BETA CAUSE IF IT WAS ON THE OPPOSITE SIDE, (DIFFERENT) SIDES, ITS AN ALPHA. IF ITS ON THE SAME SIDE: dw:1351066436831:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0SO, SAME SIDE IS BETA

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0THATS WHY THE LAST ONE THREW ME OFF

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2No, look closely its like thisdw:1351066676182:dw You include the oxygen with the first carbon (or anomeric carbon), so for this one its beta.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ITS BETA CAUSE THE CH2OH AND OH ARE ON THE SAME SIDE RIGHT?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2So, for the last one dw:1351066852933:dw is alpha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351066888242:dw CAUSE THEY ARE ON OPPOSITE SIDES?

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2dw:1351066975972:dw dw:1351066986195:dw

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2The OH determines whether its a alpha or beta, when OH is on top, its beta, when OH is on bottom, its alpha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351067070066:dw SO WHY WHEN U SWITCHED THEM DID THEY CHANGE?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OHHHHHHHHHHHH!!!!!!!!!!!! LOL THAT MAKES SENSE...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0WILL YOU BE ON HERE TOMORROW?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I NEED TO GET SOME REST. I NEED TO STUDY ALL DAY TOMORROW, BUT U HELPED ME WITH A FEW THINGS.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ITD BE COOL IF U CAN GET ON TOMORROW, AT ABOUT 8AM LOS ANGELES TIME.

.Sam.
 4 years ago
Best ResponseYou've already chosen the best response.2Okay, I see whether if I'm free at that time.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0YEA, ILL BE ON HERE BETWEN 8:30AM TO LIKE 2PM LOS ANGELES TIME

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0THANK YOU SO MUCH. I NEED TO PASS THIS TEST
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.