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my advice for you is..don't use product rule. expand (x-1)^2 first

alright so \[x^2-2x+1\]

Why not to use product rule?

right. don't forget the x
x(x^2 - 2x + 1)
now distribute x into the trinomial

@SheldonEinstein because expanding it will be a lot simpler

if you expand it, you just get a polynomial (then you can derive the terms individually)

then \[x^3-2x^2+x\]
so f'(x) = \[3x^2-4x+1\]

yes

can you show product rule with that quickly please?

put u = x and v = (x-1)^2

are you required to solve it by product rule or are you just interested @sjerman1 ?

Wait I am typing :(

i have no idea what that theorem is.....but let's see what @SheldonEinstein is typing

Sorry for late answer :( I was checking it :)

Amazing job!
Thank you very much!

You're welcome @sjerman1 ...
Thanks for the patience friends :) Also , good job @lgbasallote

i wonder, is there anyway to view these questions after they are closed?

Save the link of the question in your computer databse.

*database. This will help you to reopen it.

Thank you both!

Here the message says all.