anonymous
  • anonymous
Please show proof of Chain Rule
MIT 18.01 Single Variable Calculus (OCW)
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anonymous
  • anonymous
Please show proof of Chain Rule
MIT 18.01 Single Variable Calculus (OCW)
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
This is the proof that I was shown when I learnt the chain rule http://math.rice.edu/~cjd/chainrule.pdf
anonymous
  • anonymous
thank you so much, i will be sure to check it out!
anonymous
  • anonymous
What is there to prove. If u is differentiable function of x and x is differentiable function of t then u is diffrentiable function of t and \[\frac{ du }{ dt } = \frac{ du }{ dt }\frac{ dx }{ dx } = \frac{ du }{ dx }\frac{ dx }{ dt }\] because \[\frac{ dx }{ dx }=1\]

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