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blessbails
Group Title
Simplify the expression.
(–2 – 2i)(–4 + 6i)
>8 – 4i
>8 – 12i
>20 – 4i
>–4 – 4i
 one year ago
 one year ago
blessbails Group Title
Simplify the expression. (–2 – 2i)(–4 + 6i) >8 – 4i >8 – 12i >20 – 4i >–4 – 4i
 one year ago
 one year ago

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SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
Do you know the value for i (iota) ?
 one year ago

surdawi Group TitleBest ResponseYou've already chosen the best response.2
just multiply everything and you should get the answer (i*i=1)
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
\[\quad(–2 – 2i)(–4 + 6i) \] \[=2(–4 + 6i) 2i(4+6i)\]
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
\[\large{(22i)(4+6i)}\] \[\large{2(4) 2i(4) 2(6i) 2i(6i)}\] \[\large{8 + 8 i  12 i 12i^2}\]
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
Now since : \[\large{ i = \sqrt{1} }\] Therefore, \[\large{i^2 = (\sqrt{1})^2 = 1 }\]
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
Solving this we get : 8  4i  12 = 44i
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
Therefore the answer is : >44i
 one year ago

blessbails Group TitleBest ResponseYou've already chosen the best response.0
thank you all so much, i've got it now! @SheldonEinstein @surdawi
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
Nice!
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
mistake !
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
20 4i
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
Sorry it will be : \[\large{8 + 12  4i = 20 4i}\]
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
I am REALLY VERY VERY SORRY for that... Thanks @UnkleRhaukus for pointing it out.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.1
\[12i^2=+12\]
 one year ago

SheldonEinstein Group TitleBest ResponseYou've already chosen the best response.2
Yeah
 one year ago
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