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blessbails
 3 years ago
Simplify the expression.
(–2 – 2i)(–4 + 6i)
>8 – 4i
>8 – 12i
>20 – 4i
>–4 – 4i
blessbails
 3 years ago
Simplify the expression. (–2 – 2i)(–4 + 6i) >8 – 4i >8 – 12i >20 – 4i >–4 – 4i

This Question is Closed

SheldonEinstein
 3 years ago
Best ResponseYou've already chosen the best response.3Do you know the value for i (iota) ?

surdawi
 3 years ago
Best ResponseYou've already chosen the best response.2just multiply everything and you should get the answer (i*i=1)

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1\[\quad(–2 – 2i)(–4 + 6i) \] \[=2(–4 + 6i) 2i(4+6i)\]

SheldonEinstein
 3 years ago
Best ResponseYou've already chosen the best response.3\[\large{(22i)(4+6i)}\] \[\large{2(4) 2i(4) 2(6i) 2i(6i)}\] \[\large{8 + 8 i  12 i 12i^2}\]

SheldonEinstein
 3 years ago
Best ResponseYou've already chosen the best response.3Now since : \[\large{ i = \sqrt{1} }\] Therefore, \[\large{i^2 = (\sqrt{1})^2 = 1 }\]

SheldonEinstein
 3 years ago
Best ResponseYou've already chosen the best response.3Solving this we get : 8  4i  12 = 44i

SheldonEinstein
 3 years ago
Best ResponseYou've already chosen the best response.3Therefore the answer is : >44i

blessbails
 3 years ago
Best ResponseYou've already chosen the best response.0thank you all so much, i've got it now! @SheldonEinstein @surdawi

SheldonEinstein
 3 years ago
Best ResponseYou've already chosen the best response.3Sorry it will be : \[\large{8 + 12  4i = 20 4i}\]

SheldonEinstein
 3 years ago
Best ResponseYou've already chosen the best response.3I am REALLY VERY VERY SORRY for that... Thanks @UnkleRhaukus for pointing it out.
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