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mskyeg
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What is the equation, in standard form, of a parabola that models the values in the table?
 one year ago
 one year ago
mskyeg Group Title
What is the equation, in standard form, of a parabola that models the values in the table?
 one year ago
 one year ago

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mskyeg Group TitleBest ResponseYou've already chosen the best response.0
Possible answers: y = 6x^2 + 5x – 4 y = –4x^2 – 5x + 6 y = 5x^2 + 4x – 6 y = 4x^2 + 5x – 6
 one year ago

Godsgirl Group TitleBest ResponseYou've already chosen the best response.1
Its the last one.
 one year ago

Godsgirl Group TitleBest ResponseYou've already chosen the best response.1
All you have to do is substituted x for the numbers. When you do that to all the equations you will found out the last one works for all of them and tht is how you get f(x)
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
@Godsgirl , what if there weren't multiple choice answers to test, how would you do it?
 one year ago

Godsgirl Group TitleBest ResponseYou've already chosen the best response.1
Well they would give you the equation and tell you to figure out f(x) so what you would do is substituted the x with the numbers they give you and that is how you find f(x) and the you would add them to the chart.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
What I mean, @Godsgirl , is what if they did not give the equation. What if the only thing you had was the chart. Could you get the function from that?
 one year ago

Godsgirl Group TitleBest ResponseYou've already chosen the best response.1
You have to have the equation to solve for the function. If you don't have that you would not be able to solve for the chart.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
That is false, @Godsgirl Your method is fine in this situation where you have choices of functions to test, but if all you had was the chart, then you can get the function from it. I can show you how if you are interested.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
The points are (2,0), (0,6), and (4,78). If these all fit into f(x)=ax^2+bx+c, then we have three equations: 0=a(2)^2+b(2)+c 6=a(0)^2+b(0)+c 78=a(4)^2+b(4)+c From the second equation, we see that the yintercept is c=6, this makes the other two equations become 4a2b=6 16a+4b=84 This can be solved as a system of two linear equations to find a and b, and then you'll have your equation.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Also note that you can fit other models to these points, such as y=ax^3+bx^2+cx+d or even x=ay^+by+c, etc.
 one year ago

Godsgirl Group TitleBest ResponseYou've already chosen the best response.1
Oh okay I totally forgot about tht. Its been a while since I've been in high school. I see it now.
 one year ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Yep. That's why I don't like multiplechoice questions, it makes it to easy to guessandcheck, and doesn't teach the broader lesson.
 one year ago

Godsgirl Group TitleBest ResponseYou've already chosen the best response.1
Haha I agree with you. I graduated early. I was 16 when I did and I got a full ride to my college.
 one year ago
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