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anonymous
 3 years ago
A steel cylinder capacity 10L holds 20 Moles of O2 at 27 C an imperfection causes the gas to leak out slowly so that temperature remains Contant Ext Pressure is 1 atm The cylinder Finaaly Contain 1 atm Calculate Work Done in Calories
anonymous
 3 years ago
A steel cylinder capacity 10L holds 20 Moles of O2 at 27 C an imperfection causes the gas to leak out slowly so that temperature remains Contant Ext Pressure is 1 atm The cylinder Finaaly Contain 1 atm Calculate Work Done in Calories

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experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1this is isothermal process, work done is given by \[ n R T \log \left( V_b \over Va\right)\\ V_a = {10 \text{L}} \\ V_b = {300.4 \over 273.4}*20*22.4 \text{L}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351149292211:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351149481464:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351149608767:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351149969466:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351150077826:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I can't continue there is not Q ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Pay attention that in this case n is variable(leaking). so U is not constant(Adiabatic) So you can not find W(work) by int Pdv.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Is the answer 48.9 kJ = 11.7 Cal ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1351152257623:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think you should have how percent was leaked ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is ~11700 cal @VincentLyon.Fr

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@experimentX : \[W=2.303*n*R*T* \log\frac{ P1 }{ P2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[P1 V = nRT\] \[P1=~48atm\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0P2=1atm (given)......Can t we Do like this...?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But Not getting the Correcr Result:

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but @VincentLyon.Fr Got it correctly...)

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.1http://www.physicsforums.com/archive/index.php/t530754.html
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