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A steel cylinder capacity 10L holds 20 Moles of O2 at 27 C an imperfection causes the gas to leak out slowly so that temperature remains Contant Ext Pressure is 1 atm The cylinder Finaaly Contain 1 atm Calculate Work Done in Calories
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experimentX
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this is isothermal process, work done is given by
\[ n R T \log \left( V_b \over Va\right)\\
V_a = {10 \text{L}} \\
V_b = {300.4 \over 273.4}*20*22.4 \text{L}\]
mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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mahmit2012
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I can't continue there is not Q ?
mahmit2012
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Pay attention that in this case n is variable(leaking).
so U is not constant(Adiabatic) So you can not find W(work) by int Pdv.
Vincent-Lyon.Fr
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Is the answer 48.9 kJ = 11.7 Cal ?
mahmit2012
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mahmit2012
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I think you should have how percent was leaked ?
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it is ~11700 cal @Vincent-Lyon.Fr
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@experimentX :
\[W=2.303*n*R*T* \log\frac{ P1 }{ P2 }\]
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\[P1 V = nRT\]
\[P1=~48atm\]
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P2=1atm (given)......Can t we Do like this...?
experimentX
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i guess you can.
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But Not getting the Correcr Result:
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but @Vincent-Lyon.Fr Got it correctly...)
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@Kryten