A vessel has 6 kg of Hydrogen at pressure 'p' and temp '500K'. A small hole is made in it so that hydrogen leaks out . How much hydrogen leaks out if the final pressure is P/2 and temp falls to 300 K?
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what is the volume of 6 kg hydrogen?
Not given in the question..
this is not difficult. consider STP ... how do you find the volume of 6kg hydrogen?
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I am a vintage 1972 . It is my daughter who is posing the problem. I need to refer to text book to answer your question but it must something to do with M/m =n ( number of moles or volume into density =mass . pl help
2g of hydrogen = 1M
6kg = 6000/2
1M = 22.4 L
using this relation you will find, 6kg = 3000 moles
PV/1500000R =PV/600 Rn or n = 1500000/600 =2500
or 2500 moles i.e 500 moles are leaked out. but options are limited to gms only . pl help
2 g = 1 M
1 moles = 2 gm
500 moles = 1000 gms=1 kg but options are 2g, 3g,5g &1g. Pl help
as pv=nrt and v is constant or p/nrt is constant
so,p/n1*500=p/2*n1*300>>>>as r is constant and other are given
as initially it is 6kg i.e. 6000 moles so final is 5000moles i.e 5Kg
so answer is 5:)
But answers are (options) 2g, 3g, 5g & 1 g.
answer can't be in grams!! grams is too low.
yup i agree
I think your original mass is supposed to be in grams in which case I believe the answer is 1 gram leaks out.
yup i agree with u also
using your data i got 1 kg ... if it were 6g, probably it would have been 1g
Yeah my mistake . It is 6g and 6 kg as I mis-typed. Thanks a lot all of you.It good night at this end . Today in fact we celebrated Bijoya Dasami ( Last day of Durga Pooja ( for Bengali) and Dussera ( win over evil as celebrated in other parts of our country) So happy Dussera/ Subha Bijoya.
I am back . I have got the answer as 1g leaked out.. Thanks all of you once again.