Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A vessel has 6 kg of Hydrogen at pressure 'p' and temp '500K'. A small hole is made in it so that hydrogen leaks out . How much hydrogen leaks out if the final pressure is P/2 and temp falls to 300 K?

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

what is the volume of 6 kg hydrogen?
Not given in the question..
this is not difficult. consider STP ... how do you find the volume of 6kg hydrogen?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I am a vintage 1972 . It is my daughter who is posing the problem. I need to refer to text book to answer your question but it must something to do with M/m =n ( number of moles or volume into density =mass . pl help
yeah ... 2g of hydrogen = 1M 6kg = 6000/2 1M = 22.4 L ----------------- using this relation you will find, 6kg = 3000 moles
PV = 3000 R*500 P/2*V = n R*300 -------------- find 'n'
PV/1500000R =PV/600 Rn or n = 1500000/600 =2500 or 2500 moles i.e 500 moles are leaked out. but options are limited to gms only . pl help
2 g = 1 M
1 moles = 2 gm 500 moles = 1000 gms=1 kg but options are 2g, 3g,5g &1g. Pl help
as pv=nrt and v is constant or p/nrt is constant p1/n1rt1=p2/n2rt2 so,p/n1*500=p/2*n1*300>>>>as r is constant and other are given so, 600n2=500n1 n2=(5/6)n1 as initially it is 6kg i.e. 6000 moles so final is 5000moles i.e 5Kg :)
so answer is 5:)
But answers are (options) 2g, 3g, 5g & 1 g.
answer can't be in grams!! grams is too low.
yup i agree
I think your original mass is supposed to be in grams in which case I believe the answer is 1 gram leaks out.
yup i agree with u also
using your data i got 1 kg ... if it were 6g, probably it would have been 1g
Yeah my mistake . It is 6g and 6 kg as I mis-typed. Thanks a lot all of you.It good night at this end . Today in fact we celebrated Bijoya Dasami ( Last day of Durga Pooja ( for Bengali) and Dussera ( win over evil as celebrated in other parts of our country) So happy Dussera/ Subha Bijoya.
I am back . I have got the answer as 1g leaked out.. Thanks all of you once again.

Not the answer you are looking for?

Search for more explanations.

Ask your own question