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rosimary Group Title

Word Problem: The container that holds the water for the football team is 1/6 full. After pouring in 11 gallons of water, it is 2/3 full. How many gallons can the container hold?

  • one year ago
  • one year ago

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  1. asnaseer Group Title
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    Start by letting x represent the capacity of the container. Now, the question says it starts off as 1/6 full, so what would that be in terms of x?

    • one year ago
  2. rosimary Group Title
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    I guess, i'm not sure. I do not like word problems because they confuse me

    • one year ago
  3. asnaseer Group Title
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    Now, the question says it starts off as 1/6 full, so what would that be in terms of x?

    • one year ago
  4. rosimary Group Title
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    1/6x

    • one year ago
  5. asnaseer Group Title
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    correct, although we would usually write that as x/6

    • one year ago
  6. asnaseer Group Title
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    Next, it says that 11 gallons was poured in. So if the container currently contains x/6 gallons, and we pour in 11 more gallons, then how many gallons do we have now?

    • one year ago
  7. rosimary Group Title
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    x/6 + 11

    • one year ago
  8. asnaseer Group Title
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    perfect! :) Finally, it says that the container is nor 2/3 full - how much would 2/3 full be in terms of x?

    • one year ago
  9. asnaseer Group Title
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    *now

    • one year ago
  10. rosimary Group Title
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    2/3x

    • one year ago
  11. rosimary Group Title
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    x/6 + 11 = 2/3x?

    • one year ago
  12. asnaseer Group Title
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    great! so - summarising - we know that at the end of all this, the container contains x/6 + 11 gallons, and we also know that it is 2/3 full so it contains 2x/3 gallons. So all we need to do now is to equate the two expressions to get:\[\frac{x}{6}+11=\frac{2x}{3}\]and solve for x.

    • one year ago
  13. asnaseer Group Title
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    you're way ahead of me! :)

    • one year ago
  14. rosimary Group Title
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    the container can hold 22 gallons of water. x=22

    • one year ago
  15. asnaseer Group Title
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    The easiest way to solve fractional expressions is to try and first get rid of the fractions. So, notice that if you multiply both sides of this equation by 6 then you can get rid of the fractions.

    • one year ago
  16. asnaseer Group Title
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    yes - you are right - well done! :D

    • one year ago
  17. rosimary Group Title
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    Thank you so much for the step by step help. It helps me understand the problem.!

    • one year ago
  18. asnaseer Group Title
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    yw :)

    • one year ago
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