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sara1234

  • 3 years ago

please help me solve

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  1. Jonask
    • 3 years ago
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    45 degrees since

  2. Aperogalics
    • 3 years ago
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    Pi/4

  3. sara1234
    • 3 years ago
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    can you please explain to me how you got that?

  4. Jonask
    • 3 years ago
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    |dw:1351091765743:dw|notice that \[\frac{ \sqrt{2} }{ 2 }=\frac{ 1 }{ \sqrt{2} }\] which we remember from the triangle

  5. Aperogalics
    • 3 years ago
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    simple \[\sqrt{2}/2=1/\sqrt{2}\] it will affect only if the value is out of range

  6. sara1234
    • 3 years ago
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    what are you talking about? confused the answer is pi/4 how did you get that?

  7. Aperogalics
    • 3 years ago
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    can u answer my simple questions...........?

  8. sara1234
    • 3 years ago
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    which is?

  9. Aperogalics
    • 3 years ago
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    do u know about domain and range of sin^-1(x)???????

  10. sara1234
    • 3 years ago
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    no

  11. Aperogalics
    • 3 years ago
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    thats y u r getting confused in values

  12. Aperogalics
    • 3 years ago
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    do u want me to tell about it right now:)

  13. sara1234
    • 3 years ago
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    i just want to know how you got that answer

  14. Aperogalics
    • 3 years ago
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    sin x is basicaly defined for all values of x but -1<sin x<1 happens always when we define sin^-1 x it is a inverse or we can say just opposite to the sinx which is defined for -1<x<1 and answer lies anywhere so a basic principle regien is defined and all other area is called general area so we knoww that sin 45 = 1/\[\sqrt{2}\] so sin -1 x = 45 degree or pi/4 radians in principal region.............k

  15. Aperogalics
    • 3 years ago
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    :)

  16. Aperogalics
    • 3 years ago
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    thank u first time i feel that i deserve it.lolz:D

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