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sabika13 Group Title

How do you find the horizontal asymptote.. It says in my textbook that " to find horizontal asymptote divide numerator and denominator by x & investigate x --> +/- infinite .. I dont understand the investigation part :S

  • 2 years ago
  • 2 years ago

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  1. NickR Group Title
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    1) Put equation or function in standard form. 2) Remove everything except the biggest exponents of x found in the numerator and denominator.

    • 2 years ago
  2. tracyy Group Title
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    One way to find the horizontal asymptote: Take the highest degree of the numerator and the denominator and divide. For example, -3x^2/x^2 = -3 Horizontal asymptote is y=-3. Now if you do that and it turns out to be x/x^2, (simplifying to 1/x) your horizontal asymptote is y=0. If it ends up being x^2/x, (simplifying to x/1) then you have no horizontal asymptote.

    • 2 years ago
  3. satellite73 Group Title
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    your book is stupid, if you don't mind me saying so

    • 2 years ago
  4. sabika13 Group Title
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    LOOOLL agreed

    • 2 years ago
  5. satellite73 Group Title
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    if the degree of the numerator is larger than the degree of the denominator, there is no horizontal asymptote if the degree of the numerator is smaller than the degree of the denominator, the horizontal asymptote is \(y=0\) if the degrees are the same, the horizontal asymptote is the ratio of the leading coefficients

    • 2 years ago
  6. sabika13 Group Title
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    yaah I know that way, but on my test I have to show how I got the horizontal asymptotes by doing what it says inthe textbook

    • 2 years ago
  7. satellite73 Group Title
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    then i guess you have to do it

    • 2 years ago
  8. bmelyk Group Title
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    set your limit to +/- infinity and solve, if you come out with a number that is your horizontal asymptote

    • 2 years ago
  9. sabika13 Group Title
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    thanks!

    • 2 years ago
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