Here's the question you clicked on:
Jusaquikie
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x) = x^−6 ln x
the actual question is \[x^{-6}\ln x\] I think the derivative is \[x^{-7}-6x^{-7}\ln x \]
derivative is better written as \[\frac{1-6\ln(x)}{x^7}\] makes finding the critical points a lot easier
on critical point is 0, but that is not in the domain of your function. so you can ignore it other one solve \[1-6\ln(x)=0\]
i think part of my problem is i don't know how to solve for ln
\[1-6\ln(x)=0\] \[6\ln(x)=1\] \[\ln(x)=\frac{1}{6}\] \[x=e^{\frac{1}{6}}\]
like that you are going to have to "exponentiate" at some point
ok thanks, i know eulers number is related to natural log i just don't know how to convert back and forth. thanks for the help
\[\ln(x)=y\iff e^y=x\]
so if i had ln23 that would be e^23?
actually ln23 is 3.13 so E^3.13 = 23?