Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

the actual question is \[x^{-6}\ln x\]
I think the derivative is \[x^{-7}-6x^{-7}\ln x \]

Not the answer you are looking for?

Search for more explanations.

i think part of my problem is i don't know how to solve for ln

\[1-6\ln(x)=0\]
\[6\ln(x)=1\]
\[\ln(x)=\frac{1}{6}\]
\[x=e^{\frac{1}{6}}\]

like that
you are going to have to "exponentiate" at some point

\[\ln(x)=y\iff e^y=x\]

so if i had ln23 that would be e^23?

actually ln23 is 3.13 so E^3.13 = 23?

Not the answer you are looking for?

Search for more explanations.