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 2 years ago
2log(x3)+1 = 5
Could you break it down step by step? I'm a bit confused on how to do this algebraically
 2 years ago
2log(x3)+1 = 5 Could you break it down step by step? I'm a bit confused on how to do this algebraically

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Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Okay, first, subtract both sides by 1, what do you get?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Right, now divide both sides by 2, what do you get?

calculusfunctions
 2 years ago
Best ResponseYou've already chosen the best response.0Don't mind me. @Callisto seems to be doing a fine job teaching so I'll just observe if you don't mind? I'll only respond if you ask.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Yup! Now, take antilog for both sides. What do you get? Note: antilog = inverse of log For example, logx = 1 => 10^(logx) = 10^1 => x = 10^1 = 10

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0yikes, haha, i'm not for sure. I briefly remember antilogs but I'm not for sure what do with them

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Do you understand that example?

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0i'm starting to get it. logx = 1. I understand that but not after that

calculusfunctions
 2 years ago
Best ResponseYou've already chosen the best response.0If I may, @Callisto perhaps he'd @Egirl01 would understand if you asked her to change the logarithm form to exponential form. @Egirl01 do you know how to do that.

ByteMe
 2 years ago
Best ResponseYou've already chosen the best response.0\(\large b^x=y \rightarrow log_by=x \)

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3logx = 1 is actually just an example...  Intuitively, log a number is the value of the power of the base Let say, I have a number 100, which can be rewritten as 10^2 Now, I take log (base 10) of that number (100), so I'll get 2, since 10 to the power of 2 give me 100. (Sorry if I make it even worse...)

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0No, I understand the piece. so if its simply log, then its naturally log10, and the antilog of log10 is 1/10 right?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3antilog of log 10 is 10. \[\log^{1}(log10) = 10\] antilog is the inverse of log.

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0Alright. So then it'd be 10 (x3) = 2?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3No.... How did you get that?

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0the antilog of log 10 is 10, so log(x3) = 2 would turn to 10(x3) = 2? Obviously that is wrong. I'm a bit lost but you can continue onto the next part of solving the equation. I'll eventually figure what I'm doing wrong

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3\[log(x3) = 2\]Take antilog for both sides: \[\log^{1}(log(x3)) = \log^{1}(2)\] Perhaps you can simplify the left first.

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0I still don't quite follow, but continue on. I'll understand eventually :)

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Nope.. It's your turn to work on it... Which part you don't understand ?

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0how exactly I create the antilog from log(x3)

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Because you are doing something on both sides... You create antilog to undo the work of log...

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0So the antilog of log10 is 10, right? and the antilog of 2 is what?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Before answering you question, could you please answer few questions first?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Can we tell me what number do I have to take log on in order to get 1?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Yes. So, what number do I have to take log on in order to get 2?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Yes! How did you get this answer?

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0because you inversed it?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Yes! So, now, can you answer your question? what is \(\log^{1}2\)?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3No. Another set question questions... What is log10 (again)?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3You got it right for the right side, it's wrong for the left.

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3What is \(\log^{1}log(10)\)?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Yes. What is \(\log^{1}(log100)\)?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3What is \(\log^{1} (log1000)\)?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3So, we can see that \(\log^{1}\) of log a number is the number itself, agree?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3So, \(\log^{1} (\log y) = y\), agree?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3So, what is \(\log^{1} (log(x3))\)?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Can you simplify the following now? \[\log^{1}(log(x3)) = \log^{1}(2)\]

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Yes! Now can you solve it?

Callisto
 2 years ago
Best ResponseYou've already chosen the best response.3Nice :D and Yes! Do you understand how to solve this type of question now?

Egirl01
 2 years ago
Best ResponseYou've already chosen the best response.0yes! Thank you soooo much for your help! I really appreciate it!
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