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anonymous
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which one?
helpmeplz311
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both. its 11 problems
helpmeplz311
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help with whatever
helpmeplz311
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any help is appreciated
anonymous
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they all use the distance formula, which is pythagoras
helpmeplz311
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ok.
helpmeplz311
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can u do the first as demonstration ill try the others?
anonymous
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page B number 1 i will do if i can read it properly
helpmeplz311
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tnx
anonymous
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you have two points labelled A and B and no numbers to go with them so lets count
helpmeplz311
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mm,ok
helpmeplz311
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ok
anonymous
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to get from A to B you go 7 units right, and 2 units down
at least that is what i see
helpmeplz311
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uh huh
helpmeplz311
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let me verify
anonymous
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|dw:1351133689882:dw|
helpmeplz311
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brb,counting
helpmeplz311
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how did you get seven again?
anonymous
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we want \(d\) which is the hypotenuse of the right triangle with one side 7 and one side 2
by pythagoras, we get
\[d^2=7^2+2^2\]
\[d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}\]
anonymous
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i counted how many steps i had to go the the right
helpmeplz311
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did you count a or b?
anonymous
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i just counted them, i did not compute anything at all
just went "one, two, three, four, five, six, seven"
helpmeplz311
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ok.
helpmeplz311
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so we aare solving for the hypotnuese
helpmeplz311
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ok, so sq rt 53 is about 7.2
anonymous
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yes in each case
that is the basis for the distance formula
anonymous
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like for number 3 on the same page, from A to B is 4 steps right, 4 steps up
distance is
\[d-\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}\]