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helpmeplz311
Group Title
Help. Thanks.
http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg
You should be able to see it. Thanks:)
 2 years ago
 2 years ago
helpmeplz311 Group Title
Help. Thanks. http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg You should be able to see it. Thanks:)
 2 years ago
 2 years ago

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satellite73 Group TitleBest ResponseYou've already chosen the best response.0
which one?
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
both. its 11 problems
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
help with whatever
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
any help is appreciated
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
they all use the distance formula, which is pythagoras
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
can u do the first as demonstration ill try the others?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
page B number 1 i will do if i can read it properly
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you have two points labelled A and B and no numbers to go with them so lets count
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
to get from A to B you go 7 units right, and 2 units down at least that is what i see
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
uh huh
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
let me verify
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351133689882:dw
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
brb,counting
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
how did you get seven again?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
we want \(d\) which is the hypotenuse of the right triangle with one side 7 and one side 2 by pythagoras, we get \[d^2=7^2+2^2\] \[d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i counted how many steps i had to go the the right
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
did you count a or b?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i just counted them, i did not compute anything at all just went "one, two, three, four, five, six, seven"
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
so we aare solving for the hypotnuese
 2 years ago

helpmeplz311 Group TitleBest ResponseYou've already chosen the best response.0
ok, so sq rt 53 is about 7.2
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
yes in each case that is the basis for the distance formula
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
like for number 3 on the same page, from A to B is 4 steps right, 4 steps up distance is \[d\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}\]
 2 years ago
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