## anonymous 4 years ago Help. Thanks. http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg You should be able to see it. Thanks:)

1. anonymous

which one?

2. anonymous

both. its 11 problems

3. anonymous

help with whatever

4. anonymous

any help is appreciated

5. anonymous

they all use the distance formula, which is pythagoras

6. anonymous

ok.

7. anonymous

can u do the first as demonstration ill try the others?

8. anonymous

page B number 1 i will do if i can read it properly

9. anonymous

tnx

10. anonymous

you have two points labelled A and B and no numbers to go with them so lets count

11. anonymous

mm,ok

12. anonymous

ok

13. anonymous

to get from A to B you go 7 units right, and 2 units down at least that is what i see

14. anonymous

uh huh

15. anonymous

let me verify

16. anonymous

|dw:1351133689882:dw|

17. anonymous

brb,counting

18. anonymous

how did you get seven again?

19. anonymous

we want $$d$$ which is the hypotenuse of the right triangle with one side 7 and one side 2 by pythagoras, we get $d^2=7^2+2^2$ $d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}$

20. anonymous

i counted how many steps i had to go the the right

21. anonymous

did you count a or b?

22. anonymous

i just counted them, i did not compute anything at all just went "one, two, three, four, five, six, seven"

23. anonymous

ok.

24. anonymous

so we aare solving for the hypotnuese

25. anonymous

ok, so sq rt 53 is about 7.2

26. anonymous

yes in each case that is the basis for the distance formula

27. anonymous

like for number 3 on the same page, from A to B is 4 steps right, 4 steps up distance is $d-\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}$