anonymous
  • anonymous
Help. Thanks. http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg You should be able to see it. Thanks:)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
which one?
anonymous
  • anonymous
both. its 11 problems
anonymous
  • anonymous
help with whatever

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anonymous
  • anonymous
any help is appreciated
anonymous
  • anonymous
they all use the distance formula, which is pythagoras
anonymous
  • anonymous
ok.
anonymous
  • anonymous
can u do the first as demonstration ill try the others?
anonymous
  • anonymous
page B number 1 i will do if i can read it properly
anonymous
  • anonymous
tnx
anonymous
  • anonymous
you have two points labelled A and B and no numbers to go with them so lets count
anonymous
  • anonymous
mm,ok
anonymous
  • anonymous
ok
anonymous
  • anonymous
to get from A to B you go 7 units right, and 2 units down at least that is what i see
anonymous
  • anonymous
uh huh
anonymous
  • anonymous
let me verify
anonymous
  • anonymous
|dw:1351133689882:dw|
anonymous
  • anonymous
brb,counting
anonymous
  • anonymous
how did you get seven again?
anonymous
  • anonymous
we want \(d\) which is the hypotenuse of the right triangle with one side 7 and one side 2 by pythagoras, we get \[d^2=7^2+2^2\] \[d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}\]
anonymous
  • anonymous
i counted how many steps i had to go the the right
anonymous
  • anonymous
did you count a or b?
anonymous
  • anonymous
i just counted them, i did not compute anything at all just went "one, two, three, four, five, six, seven"
anonymous
  • anonymous
ok.
anonymous
  • anonymous
so we aare solving for the hypotnuese
anonymous
  • anonymous
ok, so sq rt 53 is about 7.2
anonymous
  • anonymous
yes in each case that is the basis for the distance formula
anonymous
  • anonymous
like for number 3 on the same page, from A to B is 4 steps right, 4 steps up distance is \[d-\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}\]

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