## helpmeplz311 2 years ago Help. Thanks. http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg You should be able to see it. Thanks:)

1. satellite73

which one?

2. helpmeplz311

both. its 11 problems

3. helpmeplz311

help with whatever

4. helpmeplz311

any help is appreciated

5. satellite73

they all use the distance formula, which is pythagoras

6. helpmeplz311

ok.

7. helpmeplz311

can u do the first as demonstration ill try the others?

8. satellite73

page B number 1 i will do if i can read it properly

9. helpmeplz311

tnx

10. satellite73

you have two points labelled A and B and no numbers to go with them so lets count

11. helpmeplz311

mm,ok

12. helpmeplz311

ok

13. satellite73

to get from A to B you go 7 units right, and 2 units down at least that is what i see

14. helpmeplz311

uh huh

15. helpmeplz311

let me verify

16. satellite73

|dw:1351133689882:dw|

17. helpmeplz311

brb,counting

18. helpmeplz311

how did you get seven again?

19. satellite73

we want $$d$$ which is the hypotenuse of the right triangle with one side 7 and one side 2 by pythagoras, we get $d^2=7^2+2^2$ $d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}$

20. satellite73

i counted how many steps i had to go the the right

21. helpmeplz311

did you count a or b?

22. satellite73

i just counted them, i did not compute anything at all just went "one, two, three, four, five, six, seven"

23. helpmeplz311

ok.

24. helpmeplz311

so we aare solving for the hypotnuese

25. helpmeplz311

ok, so sq rt 53 is about 7.2

26. satellite73

yes in each case that is the basis for the distance formula

27. satellite73

like for number 3 on the same page, from A to B is 4 steps right, 4 steps up distance is $d-\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}$