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Help. Thanks.
http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg
You should be able to see it. Thanks:)
 one year ago
 one year ago
Help. Thanks. http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg You should be able to see it. Thanks:)
 one year ago
 one year ago

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helpmeplz311Best ResponseYou've already chosen the best response.0
both. its 11 problems
 one year ago

helpmeplz311Best ResponseYou've already chosen the best response.0
help with whatever
 one year ago

helpmeplz311Best ResponseYou've already chosen the best response.0
any help is appreciated
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
they all use the distance formula, which is pythagoras
 one year ago

helpmeplz311Best ResponseYou've already chosen the best response.0
can u do the first as demonstration ill try the others?
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
page B number 1 i will do if i can read it properly
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
you have two points labelled A and B and no numbers to go with them so lets count
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
to get from A to B you go 7 units right, and 2 units down at least that is what i see
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
dw:1351133689882:dw
 one year ago

helpmeplz311Best ResponseYou've already chosen the best response.0
how did you get seven again?
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
we want \(d\) which is the hypotenuse of the right triangle with one side 7 and one side 2 by pythagoras, we get \[d^2=7^2+2^2\] \[d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
i counted how many steps i had to go the the right
 one year ago

helpmeplz311Best ResponseYou've already chosen the best response.0
did you count a or b?
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
i just counted them, i did not compute anything at all just went "one, two, three, four, five, six, seven"
 one year ago

helpmeplz311Best ResponseYou've already chosen the best response.0
so we aare solving for the hypotnuese
 one year ago

helpmeplz311Best ResponseYou've already chosen the best response.0
ok, so sq rt 53 is about 7.2
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
yes in each case that is the basis for the distance formula
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
like for number 3 on the same page, from A to B is 4 steps right, 4 steps up distance is \[d\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}\]
 one year ago
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