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helpmeplz311

  • 3 years ago

Help. Thanks. http://fotos.fotoflexer.com/e35202bc5d3c01a65b83e6b92ecb48e4.jpg You should be able to see it. Thanks:)

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  1. anonymous
    • 3 years ago
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    which one?

  2. helpmeplz311
    • 3 years ago
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    both. its 11 problems

  3. helpmeplz311
    • 3 years ago
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    help with whatever

  4. helpmeplz311
    • 3 years ago
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    any help is appreciated

  5. anonymous
    • 3 years ago
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    they all use the distance formula, which is pythagoras

  6. helpmeplz311
    • 3 years ago
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    ok.

  7. helpmeplz311
    • 3 years ago
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    can u do the first as demonstration ill try the others?

  8. anonymous
    • 3 years ago
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    page B number 1 i will do if i can read it properly

  9. helpmeplz311
    • 3 years ago
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    tnx

  10. anonymous
    • 3 years ago
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    you have two points labelled A and B and no numbers to go with them so lets count

  11. helpmeplz311
    • 3 years ago
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    mm,ok

  12. helpmeplz311
    • 3 years ago
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    ok

  13. anonymous
    • 3 years ago
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    to get from A to B you go 7 units right, and 2 units down at least that is what i see

  14. helpmeplz311
    • 3 years ago
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    uh huh

  15. helpmeplz311
    • 3 years ago
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    let me verify

  16. anonymous
    • 3 years ago
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    |dw:1351133689882:dw|

  17. helpmeplz311
    • 3 years ago
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    brb,counting

  18. helpmeplz311
    • 3 years ago
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    how did you get seven again?

  19. anonymous
    • 3 years ago
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    we want \(d\) which is the hypotenuse of the right triangle with one side 7 and one side 2 by pythagoras, we get \[d^2=7^2+2^2\] \[d=\sqrt{7^2+2^2}=\sqrt{49+4}=\sqrt{53}\]

  20. anonymous
    • 3 years ago
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    i counted how many steps i had to go the the right

  21. helpmeplz311
    • 3 years ago
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    did you count a or b?

  22. anonymous
    • 3 years ago
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    i just counted them, i did not compute anything at all just went "one, two, three, four, five, six, seven"

  23. helpmeplz311
    • 3 years ago
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    ok.

  24. helpmeplz311
    • 3 years ago
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    so we aare solving for the hypotnuese

  25. helpmeplz311
    • 3 years ago
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    ok, so sq rt 53 is about 7.2

  26. anonymous
    • 3 years ago
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    yes in each case that is the basis for the distance formula

  27. anonymous
    • 3 years ago
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    like for number 3 on the same page, from A to B is 4 steps right, 4 steps up distance is \[d-\sqrt{4^2+4^2}=\sqrt{16+16}=\sqrt{32}\]

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