## anonymous 3 years ago What is the slope of the line that passes through (5,-3) and (-2,1)

1. anonymous

m= mx+b

2. P0sitr0n

slope m = (y2-y1)/(x2-x1) 1-(-3)/-2-5=4/-7

3. anonymous

$slope=\frac{y_2-y_1}{x_2-x_1}$ Pute (x1, y1) =(5,-3) and (x2, y2) = (-2,1) into the formula.

4. P0sitr0n

no, m cant be equal to mx+b, m is the slope, not the line

5. anonymous

*put

6. anonymous

positron is right the slope is -4/7