Here's the question you clicked on:
spidergirl51
Charles has been asked to insert a trapezoid in the floor tiling of the rotunda of the courthouse. One base must be 8 feet and the height must be 10 feet. Write an equation for the area.
algebra 1 equations
so, area = (8 feet + x feet / 2) * 10
\[a=(\frac{ 8+x }{ 2 }) * 10\]
If Charles wants the area of the trapezoid to be 65 square feet, what should be the measure of the second base?
just plug 65 into a, sorry I was AFK
\[65 = ((8+x)/2)∗10\]
x will be the second side
so idk what to do first
so whats the first step
Solve for x: 65 = 5 (8+x) Divide both sides by a constant to simplify the equation. Divide both sides of 65 = 5 (8+x) by 5: 8+x = 65/5 Use long division to simplify 65/5. 5 | 1 | 3 | 6 | 5 - | 5 | | 1 | 5 - | 1 | 5 | | 0: 8+x = 13 Isolate terms with x to the left hand side. Subtract 8 from both sides: x+(8-8) = 13-8 Look for two terms that sum to zero. 8-8 = 0: x = 13-8 Evaluate 13-8. 13-8 = 5: Answer: x = 5