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spidergirl51 Group Title

Charles has been asked to insert a trapezoid in the floor tiling of the rotunda of the courthouse. One base must be 8 feet and the height must be 10 feet. Write an equation for the area.

  • one year ago
  • one year ago

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  1. spidergirl51 Group Title
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    help?

    • one year ago
  2. spidergirl51 Group Title
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    algebra 1 equations

    • one year ago
  3. gallaxhar Group Title
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    http://www.mathopenref.com/trapezoidarea.html

    • one year ago
  4. gallaxhar Group Title
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    so, area = (8 feet + x feet / 2) * 10

    • one year ago
  5. gallaxhar Group Title
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    \[a=(\frac{ 8+x }{ 2 }) * 10\]

    • one year ago
  6. spidergirl51 Group Title
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    If Charles wants the area of the trapezoid to be 65 square feet, what should be the measure of the second base?

    • one year ago
  7. spidergirl51 Group Title
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    u there?

    • one year ago
  8. gallaxhar Group Title
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    just plug 65 into a, sorry I was AFK

    • one year ago
  9. spidergirl51 Group Title
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    65=

    • one year ago
  10. gallaxhar Group Title
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    \[65 = ((8+x)/2)∗10\]

    • one year ago
  11. gallaxhar Group Title
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    x will be the second side

    • one year ago
  12. spidergirl51 Group Title
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    so idk what to do first

    • one year ago
  13. spidergirl51 Group Title
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    so whats the first step

    • one year ago
  14. gallaxhar Group Title
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    Solve for x: 65 = 5 (8+x) Divide both sides by a constant to simplify the equation. Divide both sides of 65 = 5 (8+x) by 5: 8+x = 65/5 Use long division to simplify 65/5. 5 | 1 | 3 | 6 | 5 - | 5 | | 1 | 5 - | 1 | 5 | | 0: 8+x = 13 Isolate terms with x to the left hand side. Subtract 8 from both sides: x+(8-8) = 13-8 Look for two terms that sum to zero. 8-8 = 0: x = 13-8 Evaluate 13-8. 13-8 = 5: Answer: x = 5

    • one year ago
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