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santw
 2 years ago
How do i simplify?
santw
 2 years ago
How do i simplify?

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santw
 2 years ago
Best ResponseYou've already chosen the best response.0\[5x=\frac{ \log_{}4 }{ \log_{}3 }\]

EpikRebel
 2 years ago
Best ResponseYou've already chosen the best response.0Wow this basically reminded me to refresh up on my Algebra 2.

santw
 2 years ago
Best ResponseYou've already chosen the best response.0i just don't know how i would divide 5 by log4/log3.

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2This involves the properties of logarithm. @santw loga/logb = ?

santw
 2 years ago
Best ResponseYou've already chosen the best response.0i tried that. my solutions manual gives a diff answer. @SheldonEinstein

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large{\frac{log_b m}{log_b n} = log_b {mn}}\]

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2Is the answer 0 ?

santw
 2 years ago
Best ResponseYou've already chosen the best response.0i'm trying to refrain from looking at the answers. but it shows me log4/5 log3? i'm lost.

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1So they just divided both sides by 5..?

santw
 2 years ago
Best ResponseYou've already chosen the best response.0yes. @zepdrix i think my question is. how do you divide a fraction by a fraction?

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2log(4)/log(3) /5/1 = \[\large{\frac{log(4)}{log(3)}\times \frac{1}{5}}\]

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2\[\large{\cfrac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}}\]

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1351139061407:dw

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2So this is how we divide fraction by fraction @santw got it?

santw
 2 years ago
Best ResponseYou've already chosen the best response.0got it! thanks! @SheldonEinstein

SheldonEinstein
 2 years ago
Best ResponseYou've already chosen the best response.2You're welcome and also, good work @zepdrix

zepdrix
 2 years ago
Best ResponseYou've already chosen the best response.1lol :d Yayyyy for hello kitty! \:D/
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