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santw

How do i simplify?

  • one year ago
  • one year ago

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  1. santw
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    \[5x=\frac{ \log_{}4 }{ \log_{}3 }\]

    • one year ago
  2. santw
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    i need to solve for x.

    • one year ago
  3. EpikRebel
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    Wow this basically reminded me to refresh up on my Algebra 2.

    • one year ago
  4. santw
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    i just don't know how i would divide 5 by log4/log3.

    • one year ago
  5. SheldonEinstein
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    This involves the properties of logarithm. @santw loga/logb = ?

    • one year ago
  6. SheldonEinstein
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    Wait!

    • one year ago
  7. santw
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    i tried that. my solutions manual gives a diff answer. @SheldonEinstein

    • one year ago
  8. SheldonEinstein
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    \[\large{\frac{log_b m}{log_b n} = log_b {m-n}}\]

    • one year ago
  9. SheldonEinstein
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    Is the answer 0 ?

    • one year ago
  10. santw
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    i'm trying to refrain from looking at the answers. but it shows me log4/5 log3? i'm lost.

    • one year ago
  11. santw
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    0.2524 @SheldonEinstein

    • one year ago
  12. zepdrix
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    So they just divided both sides by 5..?

    • one year ago
  13. SheldonEinstein
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    Very near lol

    • one year ago
  14. santw
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    yes. @zepdrix i think my question is. how do you divide a fraction by a fraction?

    • one year ago
  15. SheldonEinstein
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    log(4)/log(3) /5/1 = \[\large{\frac{log(4)}{log(3)}\times \frac{1}{5}}\]

    • one year ago
  16. SheldonEinstein
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    \[\large{\cfrac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}}\]

    • one year ago
  17. SheldonEinstein
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    |dw:1351139061407:dw|

    • one year ago
  18. SheldonEinstein
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    So this is how we divide fraction by fraction @santw got it?

    • one year ago
  19. santw
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    got it! thanks! @SheldonEinstein

    • one year ago
  20. SheldonEinstein
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    You're welcome and also, good work @zepdrix

    • one year ago
  21. zepdrix
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    lol :d Yayyyy for hello kitty! \:D/

    • one year ago
  22. SheldonEinstein
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    :D

    • one year ago
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