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santw

  • 3 years ago

How do i simplify?

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  1. santw
    • 3 years ago
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    \[5x=\frac{ \log_{}4 }{ \log_{}3 }\]

  2. santw
    • 3 years ago
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    i need to solve for x.

  3. EpikRebel
    • 3 years ago
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    Wow this basically reminded me to refresh up on my Algebra 2.

  4. santw
    • 3 years ago
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    i just don't know how i would divide 5 by log4/log3.

  5. SheldonEinstein
    • 3 years ago
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    This involves the properties of logarithm. @santw loga/logb = ?

  6. SheldonEinstein
    • 3 years ago
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    Wait!

  7. santw
    • 3 years ago
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    i tried that. my solutions manual gives a diff answer. @SheldonEinstein

  8. SheldonEinstein
    • 3 years ago
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    \[\large{\frac{log_b m}{log_b n} = log_b {m-n}}\]

  9. SheldonEinstein
    • 3 years ago
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    Is the answer 0 ?

  10. santw
    • 3 years ago
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    i'm trying to refrain from looking at the answers. but it shows me log4/5 log3? i'm lost.

  11. santw
    • 3 years ago
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    0.2524 @SheldonEinstein

  12. zepdrix
    • 3 years ago
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    So they just divided both sides by 5..?

  13. SheldonEinstein
    • 3 years ago
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    Very near lol

  14. santw
    • 3 years ago
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    yes. @zepdrix i think my question is. how do you divide a fraction by a fraction?

  15. SheldonEinstein
    • 3 years ago
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    log(4)/log(3) /5/1 = \[\large{\frac{log(4)}{log(3)}\times \frac{1}{5}}\]

  16. SheldonEinstein
    • 3 years ago
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    \[\large{\cfrac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}}\]

  17. SheldonEinstein
    • 3 years ago
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    |dw:1351139061407:dw|

  18. SheldonEinstein
    • 3 years ago
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    So this is how we divide fraction by fraction @santw got it?

  19. santw
    • 3 years ago
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    got it! thanks! @SheldonEinstein

  20. SheldonEinstein
    • 3 years ago
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    You're welcome and also, good work @zepdrix

  21. zepdrix
    • 3 years ago
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    lol :d Yayyyy for hello kitty! \:D/

  22. SheldonEinstein
    • 3 years ago
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    :D

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