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santw
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\[5x=\frac{ \log_{}4 }{ \log_{}3 }\]

santw
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i need to solve for x.

EpikRebel
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Wow this basically reminded me to refresh up on my Algebra 2.

santw
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i just don't know how i would divide 5 by log4/log3.

SheldonEinstein
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This involves the properties of logarithm. @santw loga/logb = ?

SheldonEinstein
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Wait!

santw
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i tried that. my solutions manual gives a diff answer. @SheldonEinstein

SheldonEinstein
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\[\large{\frac{log_b m}{log_b n} = log_b {mn}}\]

SheldonEinstein
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Is the answer 0 ?

santw
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i'm trying to refrain from looking at the answers. but it shows me
log4/5 log3?
i'm lost.

santw
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0.2524 @SheldonEinstein

zepdrix
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So they just divided both sides by 5..?

SheldonEinstein
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Very near lol

santw
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yes. @zepdrix
i think my question is. how do you divide a fraction by a fraction?

SheldonEinstein
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log(4)/log(3) /5/1 = \[\large{\frac{log(4)}{log(3)}\times \frac{1}{5}}\]

SheldonEinstein
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\[\large{\cfrac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}}\]

SheldonEinstein
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dw:1351139061407:dw

SheldonEinstein
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So this is how we divide fraction by fraction @santw got it?

santw
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got it! thanks! @SheldonEinstein

SheldonEinstein
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You're welcome and also, good work @zepdrix

zepdrix
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lol :d
Yayyyy for hello kitty! \:D/

SheldonEinstein
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:D