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santwBest ResponseYou've already chosen the best response.0
\[5x=\frac{ \log_{}4 }{ \log_{}3 }\]
 one year ago

EpikRebelBest ResponseYou've already chosen the best response.0
Wow this basically reminded me to refresh up on my Algebra 2.
 one year ago

santwBest ResponseYou've already chosen the best response.0
i just don't know how i would divide 5 by log4/log3.
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
This involves the properties of logarithm. @santw loga/logb = ?
 one year ago

santwBest ResponseYou've already chosen the best response.0
i tried that. my solutions manual gives a diff answer. @SheldonEinstein
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
\[\large{\frac{log_b m}{log_b n} = log_b {mn}}\]
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
Is the answer 0 ?
 one year ago

santwBest ResponseYou've already chosen the best response.0
i'm trying to refrain from looking at the answers. but it shows me log4/5 log3? i'm lost.
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
So they just divided both sides by 5..?
 one year ago

santwBest ResponseYou've already chosen the best response.0
yes. @zepdrix i think my question is. how do you divide a fraction by a fraction?
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
log(4)/log(3) /5/1 = \[\large{\frac{log(4)}{log(3)}\times \frac{1}{5}}\]
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
\[\large{\cfrac{\frac{a}{b}}{\frac{c}{d}} = \frac{a}{b} \times \frac{d}{c}}\]
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
dw:1351139061407:dw
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
So this is how we divide fraction by fraction @santw got it?
 one year ago

santwBest ResponseYou've already chosen the best response.0
got it! thanks! @SheldonEinstein
 one year ago

SheldonEinsteinBest ResponseYou've already chosen the best response.2
You're welcome and also, good work @zepdrix
 one year ago

zepdrixBest ResponseYou've already chosen the best response.1
lol :d Yayyyy for hello kitty! \:D/
 one year ago
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