3psilon
A particle moves in a circle of radius 90m with a constant speed of 25 m/s . What is the angular velocity in radians per second about the center of the circle?
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soty2013
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|dw:1351140725393:dw|
Aperogalics
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2*pi*r=565.484
time taken =565.484/25=22.6194sec
so \[\omega\]=2*pi/22.6194=0.2831rad/sec
Aperogalics
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:)
Algebraic!
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or V=r*omega
omega =V/r
3psilon
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That's the route I went @Algebraic!
3psilon
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But I got a small number , how do i convert it into radians
Aperogalics
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multiply it with (pi/180) which converts it into radians:)
Algebraic!
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it's already in radians /sec
Algebraic!
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.277777777777 rad.s/sec
Algebraic!
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look at it this way... it's only going 25 m/s ... it's going to take a while to go around the circle once... 2pi/.2777777777 in fact, is how long one complete rev. will take...
Algebraic!
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@aperogalics showed that explicitly...
3psilon
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ohh okay okay ! Thank you @Algebraic!