3psilon
  • 3psilon
A particle moves in a circle of radius 90m with a constant speed of 25 m/s . What is the angular velocity in radians per second about the center of the circle?
Physics
schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1351140725393:dw|
anonymous
  • anonymous
2*pi*r=565.484 time taken =565.484/25=22.6194sec so \[\omega\]=2*pi/22.6194=0.2831rad/sec
anonymous
  • anonymous
:)

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anonymous
  • anonymous
or V=r*omega omega =V/r
3psilon
  • 3psilon
That's the route I went @Algebraic!
3psilon
  • 3psilon
But I got a small number , how do i convert it into radians
anonymous
  • anonymous
multiply it with (pi/180) which converts it into radians:)
anonymous
  • anonymous
it's already in radians /sec
anonymous
  • anonymous
.277777777777 rad.s/sec
anonymous
  • anonymous
look at it this way... it's only going 25 m/s ... it's going to take a while to go around the circle once... 2pi/.2777777777 in fact, is how long one complete rev. will take...
anonymous
  • anonymous
@aperogalics showed that explicitly...
3psilon
  • 3psilon
ohh okay okay ! Thank you @Algebraic!

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