## stardust3829 3 years ago p(a)=.05a t(p)=3p t(a)=?

1. soty2013

please be more detailed while posting questions.

2. stardust3829

the variables are just variables, they don't mean anything...

3. PhoenixFire

\[p(a)=0.05a\]\[t(p)=3p\] Then \[t(a)=(3)(0.05a)\]\[t(a)=0.15a\]

4. stardust3829

How do you know how to combine the functions?

5. Yahoo!

t(p)=3p t(1) = 3*1 = 3 t(2) = 3*2 = 6 t(a) = 3*a = 3a

6. Yahoo!

To be More Specific: f(x) = 2x + 3 f(1) = 2+3 f(a) = 2a + 3

7. PhoenixFire

You haven't given us any info to say not to.. So my assumption is that p(a)=0.05a is the function way of writing p=0.05a. Therefore you can substitute that into t(p) to get \[t(a)=3(0.05a)=0.15a\]

8. Yahoo!

@stardust3829 DId u get my point

9. PhoenixFire

but @Yahoo! also has a point. Because of the lack of information this can be interpreted in different ways.

10. stardust3829

not really, a little bit, but not much :) sorry

11. stardust3829

how does knowing what the functions are saying, help to know how to combine them?

12. PhoenixFire

You've given us two functions and you want us to find a third function which returns the same variable as one of the functions but takes a different input. <<<--- confusing sentence. y=2x is the same as y(x)=2x. x being your input and y your output. now if you had say h=5y. that's the same as saying h(y)=5y... with y as your input and h your output. Now you want to find h(x). which has an input of x but an output of y. so from that you know you nee to combine the equations. you get h(y)=h(2x) and since your h=5y.. y the input. you get h(2x)=5(2x). but you want it as h(x). so you simplify the right side 5(2x)=10x.. and now your h=10x, which is the same as h(x)=10x

13. stardust3829

thank you