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soty2013 Group TitleBest ResponseYou've already chosen the best response.0
please be more detailed while posting questions.
 one year ago

stardust3829 Group TitleBest ResponseYou've already chosen the best response.0
the variables are just variables, they don't mean anything...
 one year ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.1
\[p(a)=0.05a\]\[t(p)=3p\] Then \[t(a)=(3)(0.05a)\]\[t(a)=0.15a\]
 one year ago

stardust3829 Group TitleBest ResponseYou've already chosen the best response.0
How do you know how to combine the functions?
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
t(p)=3p t(1) = 3*1 = 3 t(2) = 3*2 = 6 t(a) = 3*a = 3a
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
To be More Specific: f(x) = 2x + 3 f(1) = 2+3 f(a) = 2a + 3
 one year ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.1
You haven't given us any info to say not to.. So my assumption is that p(a)=0.05a is the function way of writing p=0.05a. Therefore you can substitute that into t(p) to get \[t(a)=3(0.05a)=0.15a\]
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
@stardust3829 DId u get my point
 one year ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.1
but @Yahoo! also has a point. Because of the lack of information this can be interpreted in different ways.
 one year ago

stardust3829 Group TitleBest ResponseYou've already chosen the best response.0
not really, a little bit, but not much :) sorry
 one year ago

stardust3829 Group TitleBest ResponseYou've already chosen the best response.0
how does knowing what the functions are saying, help to know how to combine them?
 one year ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.1
You've given us two functions and you want us to find a third function which returns the same variable as one of the functions but takes a different input. <<< confusing sentence. y=2x is the same as y(x)=2x. x being your input and y your output. now if you had say h=5y. that's the same as saying h(y)=5y... with y as your input and h your output. Now you want to find h(x). which has an input of x but an output of y. so from that you know you nee to combine the equations. you get h(y)=h(2x) and since your h=5y.. y the input. you get h(2x)=5(2x). but you want it as h(x). so you simplify the right side 5(2x)=10x.. and now your h=10x, which is the same as h(x)=10x
 one year ago

stardust3829 Group TitleBest ResponseYou've already chosen the best response.0
thank you
 one year ago
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