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stardust3829
 2 years ago
p(a)=.05a t(p)=3p t(a)=?
stardust3829
 2 years ago
p(a)=.05a t(p)=3p t(a)=?

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soty2013
 2 years ago
Best ResponseYou've already chosen the best response.0please be more detailed while posting questions.

stardust3829
 2 years ago
Best ResponseYou've already chosen the best response.0the variables are just variables, they don't mean anything...

PhoenixFire
 2 years ago
Best ResponseYou've already chosen the best response.1\[p(a)=0.05a\]\[t(p)=3p\] Then \[t(a)=(3)(0.05a)\]\[t(a)=0.15a\]

stardust3829
 2 years ago
Best ResponseYou've already chosen the best response.0How do you know how to combine the functions?

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0t(p)=3p t(1) = 3*1 = 3 t(2) = 3*2 = 6 t(a) = 3*a = 3a

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0To be More Specific: f(x) = 2x + 3 f(1) = 2+3 f(a) = 2a + 3

PhoenixFire
 2 years ago
Best ResponseYou've already chosen the best response.1You haven't given us any info to say not to.. So my assumption is that p(a)=0.05a is the function way of writing p=0.05a. Therefore you can substitute that into t(p) to get \[t(a)=3(0.05a)=0.15a\]

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0@stardust3829 DId u get my point

PhoenixFire
 2 years ago
Best ResponseYou've already chosen the best response.1but @Yahoo! also has a point. Because of the lack of information this can be interpreted in different ways.

stardust3829
 2 years ago
Best ResponseYou've already chosen the best response.0not really, a little bit, but not much :) sorry

stardust3829
 2 years ago
Best ResponseYou've already chosen the best response.0how does knowing what the functions are saying, help to know how to combine them?

PhoenixFire
 2 years ago
Best ResponseYou've already chosen the best response.1You've given us two functions and you want us to find a third function which returns the same variable as one of the functions but takes a different input. <<< confusing sentence. y=2x is the same as y(x)=2x. x being your input and y your output. now if you had say h=5y. that's the same as saying h(y)=5y... with y as your input and h your output. Now you want to find h(x). which has an input of x but an output of y. so from that you know you nee to combine the equations. you get h(y)=h(2x) and since your h=5y.. y the input. you get h(2x)=5(2x). but you want it as h(x). so you simplify the right side 5(2x)=10x.. and now your h=10x, which is the same as h(x)=10x
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