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stardust3829

  • 2 years ago

p(a)=.05a t(p)=3p t(a)=?

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  1. soty2013
    • 2 years ago
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    please be more detailed while posting questions.

  2. stardust3829
    • 2 years ago
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    the variables are just variables, they don't mean anything...

  3. PhoenixFire
    • 2 years ago
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    \[p(a)=0.05a\]\[t(p)=3p\] Then \[t(a)=(3)(0.05a)\]\[t(a)=0.15a\]

  4. stardust3829
    • 2 years ago
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    How do you know how to combine the functions?

  5. Yahoo!
    • 2 years ago
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    t(p)=3p t(1) = 3*1 = 3 t(2) = 3*2 = 6 t(a) = 3*a = 3a

  6. Yahoo!
    • 2 years ago
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    To be More Specific: f(x) = 2x + 3 f(1) = 2+3 f(a) = 2a + 3

  7. PhoenixFire
    • 2 years ago
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    You haven't given us any info to say not to.. So my assumption is that p(a)=0.05a is the function way of writing p=0.05a. Therefore you can substitute that into t(p) to get \[t(a)=3(0.05a)=0.15a\]

  8. Yahoo!
    • 2 years ago
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    @stardust3829 DId u get my point

  9. PhoenixFire
    • 2 years ago
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    but @Yahoo! also has a point. Because of the lack of information this can be interpreted in different ways.

  10. stardust3829
    • 2 years ago
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    not really, a little bit, but not much :) sorry

  11. stardust3829
    • 2 years ago
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    how does knowing what the functions are saying, help to know how to combine them?

  12. PhoenixFire
    • 2 years ago
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    You've given us two functions and you want us to find a third function which returns the same variable as one of the functions but takes a different input. <<<--- confusing sentence. y=2x is the same as y(x)=2x. x being your input and y your output. now if you had say h=5y. that's the same as saying h(y)=5y... with y as your input and h your output. Now you want to find h(x). which has an input of x but an output of y. so from that you know you nee to combine the equations. you get h(y)=h(2x) and since your h=5y.. y the input. you get h(2x)=5(2x). but you want it as h(x). so you simplify the right side 5(2x)=10x.. and now your h=10x, which is the same as h(x)=10x

  13. stardust3829
    • 2 years ago
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    thank you

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