Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

p(a)=.05a t(p)=3p t(a)=?

I got my questions answered at in under 10 minutes. Go to now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

please be more detailed while posting questions.
the variables are just variables, they don't mean anything...
\[p(a)=0.05a\]\[t(p)=3p\] Then \[t(a)=(3)(0.05a)\]\[t(a)=0.15a\]

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

How do you know how to combine the functions?
t(p)=3p t(1) = 3*1 = 3 t(2) = 3*2 = 6 t(a) = 3*a = 3a
To be More Specific: f(x) = 2x + 3 f(1) = 2+3 f(a) = 2a + 3
You haven't given us any info to say not to.. So my assumption is that p(a)=0.05a is the function way of writing p=0.05a. Therefore you can substitute that into t(p) to get \[t(a)=3(0.05a)=0.15a\]
@stardust3829 DId u get my point
but @Yahoo! also has a point. Because of the lack of information this can be interpreted in different ways.
not really, a little bit, but not much :) sorry
how does knowing what the functions are saying, help to know how to combine them?
You've given us two functions and you want us to find a third function which returns the same variable as one of the functions but takes a different input. <<<--- confusing sentence. y=2x is the same as y(x)=2x. x being your input and y your output. now if you had say h=5y. that's the same as saying h(y)=5y... with y as your input and h your output. Now you want to find h(x). which has an input of x but an output of y. so from that you know you nee to combine the equations. you get h(y)=h(2x) and since your h=5y.. y the input. you get h(2x)=5(2x). but you want it as h(x). so you simplify the right side 5(2x)=10x.. and now your h=10x, which is the same as h(x)=10x
thank you

Not the answer you are looking for?

Search for more explanations.

Ask your own question