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anonymous
 4 years ago
I have two complex numbers:
z1=a+ib and z2=c+id
I am supposed to write them in that form: z=(rcos(theta), rain(theta)).
Using that form I need to prove that theta of z3 (z3=z1*z2) is theta of z1 + theta of z2.
Using the e^itheta from of complex numbers that would be simple problem but in that component form I can not find a way to prove that.
anonymous
 4 years ago
I have two complex numbers: z1=a+ib and z2=c+id I am supposed to write them in that form: z=(rcos(theta), rain(theta)). Using that form I need to prove that theta of z3 (z3=z1*z2) is theta of z1 + theta of z2. Using the e^itheta from of complex numbers that would be simple problem but in that component form I can not find a way to prove that.

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here is what I got up till now.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Cosx + i sinx = e^(ix) == Euclear Theorem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Aw, I think I am not allowed to use the "e" from. I am supposed to write the complex number as a vector in the form (radius*cos(angle) , radius*sin(angle)). Writing it like that I must prove that the angles add if I multiply two complex numbers.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Let a= r cos theta, b= r sin theta, c= s sin gamma, d= s cos gamma, r= (a^2+b^2)^1/2, s=(c^2+d^2)^1/2 Substitute into your equation, throw a few trig substitutions at it, and declare victory.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do I am on the right way (on the picture)? I just need to work in the radius?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Put the substitutions above into the equation you have for Z3, and look for a sum of angles trig identity to work backwards to your desired result.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k, I will try to do that. Thank you for your time and help, AnimalAin.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You should end up with \[z_3 = rs(\cos (\theta + \gamma)+i \sin(\theta + \gamma)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Have fun. Do math every day.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thx, I just did the calculation and it worked out just fine. Thank you for your help, AnimalAin. Now I can claim VICTORY! ;)
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