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lgbasallote
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Evaluate: \[[\neg p \wedge (p \vee q)] \rightarrow q\]
 2 years ago
 2 years ago
lgbasallote Group Title
Evaluate: \[[\neg p \wedge (p \vee q)] \rightarrow q\]
 2 years ago
 2 years ago

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lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i suppse \[\neg p \wedge (p \vee q) \equiv p\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so then it becomes \[p \rightarrow q\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
then what?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
oh i see
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i made a mistake
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
\[\neg p \wedge (p \vee q) \equiv F \vee (\neg p \wedge q) \rightarrow q\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
then this becomes \[T \wedge (p \vee q) \vee q\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
then \[T \wedge (p \vee q) \equiv p \vee q \]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
in my solution i will be treating them the same....my latex is gonna get confusing if i follow the rules
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
\[\equiv p \vee q \vee q\] \[q \vee q \equiv T\] so.. \[\equiv p \vee T \equiv T\] yes?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so then this is a tautology?
 2 years ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
implication law is P>Q=nP V Q Right? Sorry for no Latex,
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
so is that a yes to my question?
 2 years ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
yes it's a tautology, but you messed something up and somehow ended up with a tautology anyways lol
 2 years ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[\small¬p∧(p∨q)\Rightarrow q\iff(\neg p\wedge p) \vee(\neg p\lor q)\Rightarrow q\iff (\neg p\lor q)\Rightarrow q \iff (\neg p\Rightarrow q)\vee(q\Rightarrow q )\]\[\iff q\Rightarrow q\qquad \top\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm looks different...
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
implication is distributive?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
seems you're the one who went wrong @PhoenixFire ....
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
\[(\neg p \wedge q) \rightarrow q\] should become \[\neg(\neg p \wedge q) \vee q\] by DM law \[p \vee q \vee q\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
hmm seems i missed a step too
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
nevertheless, important thing is.. i was right....that was my question in the first place anyways
 2 years ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
de morgans law.... you have to negate both. n(nP ^ Q) V Q becomes nnP V nQ V Q
 2 years ago

PhoenixFire Group TitleBest ResponseYou've already chosen the best response.0
nnP < Involution law becomes P. What you missed was distributing the negative to the Q during De Morgan's Law
 2 years ago
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