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powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351156478191:dw
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
how can you find b in \[\frac{x^2}{3^2}  \frac{y^2}{b^2} =1 \] v?
 one year ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
@Jonask is correct
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
do i sub (4,0) in ?
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
The foci are (plus/minus a*e,0) where the eccentricity e = sqrt(1+ (b^2/a^2))
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
? what do i do what tiwtha
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
whats interecept??
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
foci, 4 = 4/e < e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
can do intercept way??
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
What is "intercept way"? What intercept?
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
@Jonask ??
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
the intercept only works in an ellipse i thought you drew an ellipse
 one year ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
@estudier is correct
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
S/B foci, 4 = 3/e < e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Can u do this? It is not difficult.
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
i think you can find by subbing in a point.. but i dunno which point
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
yeah but i dont think i can remember ..
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
can you find the corodinate of point directly above foci??
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
foci, 4 = 3/e > e = 4/3 = sqrt( 1 + b^2/3^2)) Solve for b^2 So 4/3 = sqt(1 + b^2/3^2) > b^2 = 12/9
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
yeah but i dont wanna remember that if in test _
 one year ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
they are related by a^2+b^2=c^2 as well right
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
U can say c^2 = a^2 b^2 (same thing)
 one year ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Actually, I made mistake in figures: 4/3 = sqrt(1 +b^2/3^2) > 16/9 = 1 + b^2/3^2 > 3^2 * 16/9 = 3^2 + b^2 > b^2 = 3^2 (16/9 1) = 3^2 *7/9 = 7 You can check it here http://www.wolframalpha.com/input/?i=%28x^2%2F3^2%29+++++y^2%2F7+%3D+1
 one year ago
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