A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
hyperbola help
anonymous
 4 years ago
hyperbola help

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1351156478191:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how can you find b in \[\frac{x^2}{3^2}  \frac{y^2}{b^2} =1 \] v?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The foci are (plus/minus a*e,0) where the eccentricity e = sqrt(1+ (b^2/a^2))

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0? what do i do what tiwtha

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0foci, 4 = 4/e < e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can do intercept way??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0What is "intercept way"? What intercept?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the intercept only works in an ellipse i thought you drew an ellipse

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0S/B foci, 4 = 3/e < e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can u do this? It is not difficult.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think you can find by subbing in a point.. but i dunno which point

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but i dont think i can remember ..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you find the corodinate of point directly above foci??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0foci, 4 = 3/e > e = 4/3 = sqrt( 1 + b^2/3^2)) Solve for b^2 So 4/3 = sqt(1 + b^2/3^2) > b^2 = 12/9

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah but i dont wanna remember that if in test _

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0they are related by a^2+b^2=c^2 as well right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0U can say c^2 = a^2 b^2 (same thing)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Actually, I made mistake in figures: 4/3 = sqrt(1 +b^2/3^2) > 16/9 = 1 + b^2/3^2 > 3^2 * 16/9 = 3^2 + b^2 > b^2 = 3^2 (16/9 1) = 3^2 *7/9 = 7 You can check it here http://www.wolframalpha.com/input/?i=%28x^2%2F3^2%29+++++y^2%2F7+%3D+1
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.