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powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
dw:1351156478191:dw
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
how can you find b in \[\frac{x^2}{3^2}  \frac{y^2}{b^2} =1 \] v?
 2 years ago

soty2013 Group TitleBest ResponseYou've already chosen the best response.0
@Jonask is correct
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
do i sub (4,0) in ?
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
The foci are (plus/minus a*e,0) where the eccentricity e = sqrt(1+ (b^2/a^2))
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
? what do i do what tiwtha
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
whats interecept??
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
foci, 4 = 4/e < e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
can do intercept way??
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
What is "intercept way"? What intercept?
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
@Jonask ??
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
the intercept only works in an ellipse i thought you drew an ellipse
 2 years ago

Jonask Group TitleBest ResponseYou've already chosen the best response.1
@estudier is correct
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
S/B foci, 4 = 3/e < e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Can u do this? It is not difficult.
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
i think you can find by subbing in a point.. but i dunno which point
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
yeah but i dont think i can remember ..
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
can you find the corodinate of point directly above foci??
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
foci, 4 = 3/e > e = 4/3 = sqrt( 1 + b^2/3^2)) Solve for b^2 So 4/3 = sqt(1 + b^2/3^2) > b^2 = 12/9
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
yeah but i dont wanna remember that if in test _
 2 years ago

powerangers69 Group TitleBest ResponseYou've already chosen the best response.0
they are related by a^2+b^2=c^2 as well right
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
U can say c^2 = a^2 b^2 (same thing)
 2 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Actually, I made mistake in figures: 4/3 = sqrt(1 +b^2/3^2) > 16/9 = 1 + b^2/3^2 > 3^2 * 16/9 = 3^2 + b^2 > b^2 = 3^2 (16/9 1) = 3^2 *7/9 = 7 You can check it here http://www.wolframalpha.com/input/?i=%28x^2%2F3^2%29+++++y^2%2F7+%3D+1
 2 years ago
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