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|dw:1351156478191:dw|

how can you find b in \[\frac{x^2}{3^2} - \frac{y^2}{b^2} =1 \] v?

intercept

do i sub (4,0) in ?

The foci are (plus/minus a*e,0) where the eccentricity
e = sqrt(1+ (b^2/a^2))

? what do i do what tiwtha

whats interecept??

foci, 4 = 4/e -< e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

can do intercept way??

What is "intercept way"? What intercept?

the intercept only works in an ellipse i thought you drew an ellipse

S/B
foci, 4 = 3/e -< e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

Can u do this? It is not difficult.

i think you can find by subbing in a point.. but i dunno which point

yeah but i dont think i can remember ..

can you find the corodinate of point directly above foci??

foci, 4 = 3/e -> e = 4/3 = sqrt( 1 + b^2/3^2)) Solve for b^2
So 4/3 = sqt(1 + b^2/3^2) -> b^2 = 12/9

yeah but i dont wanna remember that if in test -_-

they are related by a^2+b^2=c^2 as well right

U can say c^2 = a^2 -b^2 (same thing)