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powerangers69

  • 3 years ago

hyperbola help

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  1. powerangers69
    • 3 years ago
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    |dw:1351156478191:dw|

  2. powerangers69
    • 3 years ago
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    how can you find b in \[\frac{x^2}{3^2} - \frac{y^2}{b^2} =1 \] v?

  3. Jonask
    • 3 years ago
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    intercept

  4. soty2013
    • 3 years ago
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    @Jonask is correct

  5. powerangers69
    • 3 years ago
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    do i sub (4,0) in ?

  6. estudier
    • 3 years ago
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    The foci are (plus/minus a*e,0) where the eccentricity e = sqrt(1+ (b^2/a^2))

  7. powerangers69
    • 3 years ago
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    ? what do i do what tiwtha

  8. powerangers69
    • 3 years ago
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    whats interecept??

  9. estudier
    • 3 years ago
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    foci, 4 = 4/e -< e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

  10. powerangers69
    • 3 years ago
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    can do intercept way??

  11. estudier
    • 3 years ago
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    What is "intercept way"? What intercept?

  12. powerangers69
    • 3 years ago
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    @Jonask ??

  13. Jonask
    • 3 years ago
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    the intercept only works in an ellipse i thought you drew an ellipse

  14. Jonask
    • 3 years ago
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    @estudier is correct

  15. estudier
    • 3 years ago
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    S/B foci, 4 = 3/e -< e = 1 = sqrt( 1 + b^2/3^2)) Solve for b^2

  16. estudier
    • 3 years ago
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    Can u do this? It is not difficult.

  17. powerangers69
    • 3 years ago
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    i think you can find by subbing in a point.. but i dunno which point

  18. powerangers69
    • 3 years ago
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    yeah but i dont think i can remember ..

  19. powerangers69
    • 3 years ago
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    can you find the corodinate of point directly above foci??

  20. estudier
    • 3 years ago
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    foci, 4 = 3/e -> e = 4/3 = sqrt( 1 + b^2/3^2)) Solve for b^2 So 4/3 = sqt(1 + b^2/3^2) -> b^2 = 12/9

  21. powerangers69
    • 3 years ago
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    yeah but i dont wanna remember that if in test -_-

  22. powerangers69
    • 3 years ago
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    they are related by a^2+b^2=c^2 as well right

  23. estudier
    • 3 years ago
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    U can say c^2 = a^2 -b^2 (same thing)

  24. estudier
    • 3 years ago
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    Actually, I made mistake in figures: 4/3 = sqrt(1 +b^2/3^2) -> 16/9 = 1 + b^2/3^2 -> 3^2 * 16/9 = 3^2 + b^2 -> b^2 = 3^2 (16/9 -1) = 3^2 *7/9 = 7 You can check it here http://www.wolframalpha.com/input/?i=%28x^2%2F3^2%29++++-+y^2%2F7+%3D+1

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