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The angular Displacement x (rad) of a wheel undergoing Rotation is given by x=4t2t^2. The Speed of particle on the rim 2s after it comes to memtary rest in 6m/s. The Diameter of wheel is?
 one year ago
 one year ago
The angular Displacement x (rad) of a wheel undergoing Rotation is given by x=4t2t^2. The Speed of particle on the rim 2s after it comes to memtary rest in 6m/s. The Diameter of wheel is?
 one year ago
 one year ago

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experimentXBest ResponseYou've already chosen the best response.1
the find the angular speed by w = dx/dt put t=2, and get angular velocity ... use relation wr = s => w*r = 6 to find r.
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
W = 4  4t at t=2 48 = 4 Wr = V r = V/W = 6/4 = 3/2 d = 3
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
seems okay ... what's the answer?
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
i dont knw but the options are 0.5 0.75 1.5 2
 one year ago
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