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SirMathy

  • 3 years ago

The depth of water in a glass at each time is measured, as coloured water flowed in at a constant rate. The results are tabulated below: T (s) V (mL) 10 2 20 2.6 30 3 40 3.3 50 3.5 60 3.7 70 3.9 80 4.1 90 4.3 100 4.4 1) Determine the depth of water in the glass as a function of time. Assume that depth at t=0 is 0cm. 2) Using geometry, determine a theoretical equation for the depth as a function of time.

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  1. CliffSedge
    • 3 years ago
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    Wouldn't you need to know the width of the glass?

  2. estudier
    • 3 years ago
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    I guess "V" is supposed to be depth.....

  3. CliffSedge
    • 3 years ago
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    But V is in units of milliliters . . .

  4. CliffSedge
    • 3 years ago
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    It can be done keeping the base area of the glass as a variable expression. Maybe assume it is a cylinder and let r = radius?

  5. SirMathy
    • 3 years ago
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    the radius is 3.2cm and the depth is 4.8cm

  6. soty2013
    • 3 years ago
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    @CliffSedge you just keep answering. you too are useless like me ... as you said me earlier, you could be suspended soon.

  7. CliffSedge
    • 3 years ago
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    @soty2013 What?

  8. CliffSedge
    • 3 years ago
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    A radius of 3.2 cm implies a base area of π(3.2)^2 cm^2. Divide the volume by that area to get the height.

  9. SirMathy
    • 3 years ago
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    for the V(ml), it is meant to be D(cm)

  10. estudier
    • 3 years ago
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    Questions 1 and 2 seem to be the same question now.... From 40 to 90, depth goes up by 0.2 per 10 secs so if we take that as the "real" rate Depth = 0.02t

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