anonymous
  • anonymous
The depth of water in a glass at each time is measured, as coloured water flowed in at a constant rate. The results are tabulated below: T (s) V (mL) 10 2 20 2.6 30 3 40 3.3 50 3.5 60 3.7 70 3.9 80 4.1 90 4.3 100 4.4 1) Determine the depth of water in the glass as a function of time. Assume that depth at t=0 is 0cm. 2) Using geometry, determine a theoretical equation for the depth as a function of time.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Wouldn't you need to know the width of the glass?
anonymous
  • anonymous
I guess "V" is supposed to be depth.....
anonymous
  • anonymous
But V is in units of milliliters . . .

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anonymous
  • anonymous
It can be done keeping the base area of the glass as a variable expression. Maybe assume it is a cylinder and let r = radius?
anonymous
  • anonymous
the radius is 3.2cm and the depth is 4.8cm
anonymous
  • anonymous
@CliffSedge you just keep answering. you too are useless like me ... as you said me earlier, you could be suspended soon.
anonymous
  • anonymous
@soty2013 What?
anonymous
  • anonymous
A radius of 3.2 cm implies a base area of π(3.2)^2 cm^2. Divide the volume by that area to get the height.
anonymous
  • anonymous
for the V(ml), it is meant to be D(cm)
anonymous
  • anonymous
Questions 1 and 2 seem to be the same question now.... From 40 to 90, depth goes up by 0.2 per 10 secs so if we take that as the "real" rate Depth = 0.02t

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