Here's the question you clicked on:
SirMathy
The depth of water in a glass at each time is measured, as coloured water flowed in at a constant rate. The results are tabulated below: T (s) V (mL) 10 2 20 2.6 30 3 40 3.3 50 3.5 60 3.7 70 3.9 80 4.1 90 4.3 100 4.4 1) Determine the depth of water in the glass as a function of time. Assume that depth at t=0 is 0cm. 2) Using geometry, determine a theoretical equation for the depth as a function of time.
Wouldn't you need to know the width of the glass?
I guess "V" is supposed to be depth.....
But V is in units of milliliters . . .
It can be done keeping the base area of the glass as a variable expression. Maybe assume it is a cylinder and let r = radius?
the radius is 3.2cm and the depth is 4.8cm
@CliffSedge you just keep answering. you too are useless like me ... as you said me earlier, you could be suspended soon.
A radius of 3.2 cm implies a base area of π(3.2)^2 cm^2. Divide the volume by that area to get the height.
for the V(ml), it is meant to be D(cm)
Questions 1 and 2 seem to be the same question now.... From 40 to 90, depth goes up by 0.2 per 10 secs so if we take that as the "real" rate Depth = 0.02t