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a[]={0,1,2,3,4,5,6,7,8,9,10};
i=0;
a[i]=a[++i+a[++i]]+a[++i];
cout<<a[i];
ans 9 whats the logic?
 one year ago
 one year ago
a[]={0,1,2,3,4,5,6,7,8,9,10}; i=0; a[i]=a[++i+a[++i]]+a[++i]; cout<<a[i]; ans 9 whats the logic?
 one year ago
 one year ago

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Matrix65Best ResponseYou've already chosen the best response.0
cout<<a[9]; //if u output 9
 one year ago

03225186213Best ResponseYou've already chosen the best response.0
i know ans is 9 how it came(evaluated)?
 one year ago

jon.stromer.galleyBest ResponseYou've already chosen the best response.1
This is a test of your understanding of order of operations. At std::cout you should see that i == 3. What is a[ 3 + a[3]] + a[3]?
 one year ago

03225186213Best ResponseYou've already chosen the best response.0
i evaluated like a[1+a[2]]+a[3]; tell me the logic of 3 at all places
 one year ago

jon.stromer.galleyBest ResponseYou've already chosen the best response.1
++i is evaluated first, so the function is: a[ 3 + a[3]] + a[3] not a[1+a[2]]+a[3] thus a[ 3 + a[3]] + a[3] == a[3 +3] + 3 == a[6] + 3 == 6 + 3 == 9
 one year ago
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