Here's the question you clicked on:
Biancao9o3o12
0<-8b<12 Solve compound Inequality PLEASE THIS IS DUE TODAY !
divide each side by -8, so you get (0/-8) <b<(12/-8)
iS THAT THE ASNWER ?
divide by \(-8\) and flip the inequalities because \(-8\) is negative
there is no such number for one thing for another, you have to change the inequalities when dividing by a negative number \[0<-/b<12\iff \frac{8}{-8}>b>\frac{12}{-8}\]
Am really sorry but I only need the answer and how to do it this is due in an hour so please I need the answer and steps how to get it I know it sounds rude and bad but I don't get any of thsi