Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

mvO

  • 3 years ago

Please Solve the following differential equation y'−2⋅y=−9+(−10)⋅x Given: y(0) = 13

  • This Question is Open
  1. pasta
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y'=4

  2. pasta
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=9+10x+y', 13=9+10(0)+y' y'=13-9 y'=4

  3. RafaMat
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[y'-2y=-9-10x.\ |y(0)=13.=>\] \[\int\limits y '-2y=\int\limits -9-10x=>\] \[y-y^2+K_1=-9x-5x^2+K_2=>\] \[y(1-y)=-9x-5x^2+K_1+K_2=>\]\[If \ y(0)=13,\ => y(1-y)=13.(1-13)=-9.0-5.0^2+K=>\]\[ ∴K=-156\]\[y(1-y)=-9x-5x^2-156\]

  4. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy