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Please Solve the following differential equation y'−2⋅y=−9+(−10)⋅x Given: y(0) = 13
y=9+10x+y', 13=9+10(0)+y' y'=13-9 y'=4
\[y'-2y=-9-10x.\ |y(0)=13.=>\] \[\int\limits y '-2y=\int\limits -9-10x=>\] \[y-y^2+K_1=-9x-5x^2+K_2=>\] \[y(1-y)=-9x-5x^2+K_1+K_2=>\]\[If \ y(0)=13,\ => y(1-y)=13.(1-13)=-9.0-5.0^2+K=>\]\[ ∴K=-156\]\[y(1-y)=-9x-5x^2-156\]