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Biancao9o3o12 Group Title

|2x-7|-1>0 solution or inequality ?

  • 2 years ago
  • 2 years ago

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  1. soty2013 Group Title
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    @ParthKohli

    • 2 years ago
  2. ParthKohli Group Title
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    |2x - 7| > 1 So 2x - 7 > 1 or 2x - 7 < -1

    • 2 years ago
  3. Biancao9o3o12 Group Title
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    So solution ?

    • 2 years ago
  4. ParthKohli Group Title
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    Solve both equations.

    • 2 years ago
  5. CliffSedge Group Title
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    ^ "inequalities," not "equations," Grammar Nazi. ;-)

    • 2 years ago
  6. Biancao9o3o12 Group Title
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    I don't get it -_-

    • 2 years ago
  7. CliffSedge Group Title
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    Solve the inequalities as if they were equations.

    • 2 years ago
  8. Biancao9o3o12 Group Title
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    @ParthKohli if I solve them they will get the same answer

    • 2 years ago
  9. ParthKohli Group Title
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    Sorry, I had an absolute value equation running in my mind. lol

    • 2 years ago
  10. CliffSedge Group Title
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    Not so, one equals 1, the other equals -1.

    • 2 years ago
  11. Biancao9o3o12 Group Title
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    So it is a solution ?

    • 2 years ago
  12. CliffSedge Group Title
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    There are two solutions because you have two equations (inequalities).

    • 2 years ago
  13. Biancao9o3o12 Group Title
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    @CliffSedge I get that but my test is only asking me if it's a solution or an inequality

    • 2 years ago
  14. CliffSedge Group Title
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    Treat 2x - 7 > 1 2x - 7 < -1 As if it were 2x - 7 = 1 2x - 7 = -1 and solve both for x.

    • 2 years ago
  15. Biancao9o3o12 Group Title
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    Oh so that's the equation ?

    • 2 years ago
  16. CliffSedge Group Title
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    "...my test is only asking me if it's a solution or an inequality " I don't understand that question. You can find a solution to the statement and the solution will be an inequality.

    • 2 years ago
  17. Biancao9o3o12 Group Title
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    My book says solve for each inequality. If there is no solution write no solution

    • 2 years ago
  18. CliffSedge Group Title
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    Ok, then solve the inequalities as I explained.

    • 2 years ago
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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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