Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

richyw Group TitleBest ResponseYou've already chosen the best response.0
how would I put \[Z=\frac{1}{\frac{1}{R}+i\left(\omega C  \frac{1}{\omega L}\right)}\] into its exponential form?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
I would first try to put it in the form z=a+bi if possible.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
are \(R, \omega,L, C\) some real constants?
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
@CliffSedge I am trying to do that I multiplied by the complex conjugate and got \[Z=\frac{Ri\left(R^2(\omega C\frac{1}{\omega L}\right)}{1+R^2\left( \omega C\frac{1}{\omega L}\right)}\]
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
is this the right step? then \[a=\frac{R}{1+R^2\left( \omega C\frac{1}{\omega L}\right)}\]and \[b=\frac{R^2\left(\omega C\frac{1}{\omega L}\right)}{1+R^2\left( \omega C\frac{1}{\omega L}\right)}\] Z=\frac{Ri\left(R^2(\omega C\frac{1}{\omega L}\right)}{1+R^2\left( \omega C\frac{1}{\omega L}\right)}
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
oops the, \(wC1/wL\) in the denominator of the above three is squared
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
I think that's an ok way to go.
 2 years ago

richyw Group TitleBest ResponseYou've already chosen the best response.0
I am so unbelievably lost man. this sucks.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
What about what satellite asked, is everything besides the i a real number constant? If so, you can simplify the form with a substitution.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
If you let \[\large u=\frac{1}{R}\] and \[\large v=\omega C\frac{1}{\omega L}\] then you can operate on \[\large z=\frac{1}{u+v i}\]
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
That might make some of the algebra easier for the intermediate steps, then you can resubstitute at the end.
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.