Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
@ghazi @Aperogalics
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
it is already solved lol
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
dw:1351178590831:dw \[T=\frac{ mv^2 }{ r }\]
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
i think you are done
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
Tmgcosx = mv^2/r
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
but hw Do i Find the angle....)
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
\[\sin \theta =\frac{ a \cos \theta }{ T }\]
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
a  tangential acceleration component
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
mgsinx = ma ....?
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
nope, just from the diagram i took it
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.1
i aksed mgsinx = ma...is it correct
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
dw:1351179063684:dw
 2 years ago

ghazi Group TitleBest ResponseYou've already chosen the best response.3
yea your equation seems correct but why to go for that when things are done here
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.