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Solve?

  • one year ago
  • one year ago

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    http://assets.openstudy.com/updates/attachments/507ec9d8e4b0599919842d03-derrick902-1350486503156-capture.jpg

    • one year ago
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    @ghazi @Aperogalics

    • one year ago
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    it is already solved lol

    • one year ago
  4. ghazi Group Title
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    |dw:1351178590831:dw| \[T=\frac{ mv^2 }{ r }\]

    • one year ago
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    i think you are done

    • one year ago
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    T-mgcosx = mv^2/r

    • one year ago
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    but hw Do i Find the angle....)

    • one year ago
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    \[\sin \theta =\frac{ a \cos \theta }{ T }\]

    • one year ago
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    a -- tangential acceleration component

    • one year ago
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    mgsinx = ma ....?

    • one year ago
  11. ghazi Group Title
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    nope, just from the diagram i took it

    • one year ago
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    i aksed mgsinx = ma...is it correct

    • one year ago
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    |dw:1351179063684:dw|

    • one year ago
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    yea your equation seems correct but why to go for that when things are done here

    • one year ago
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