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ghaziBest ResponseYou've already chosen the best response.3
it is already solved lol
 one year ago

ghaziBest ResponseYou've already chosen the best response.3
dw:1351178590831:dw \[T=\frac{ mv^2 }{ r }\]
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
but hw Do i Find the angle....)
 one year ago

ghaziBest ResponseYou've already chosen the best response.3
\[\sin \theta =\frac{ a \cos \theta }{ T }\]
 one year ago

ghaziBest ResponseYou've already chosen the best response.3
a  tangential acceleration component
 one year ago

ghaziBest ResponseYou've already chosen the best response.3
nope, just from the diagram i took it
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.1
i aksed mgsinx = ma...is it correct
 one year ago

ghaziBest ResponseYou've already chosen the best response.3
yea your equation seems correct but why to go for that when things are done here
 one year ago
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