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ali_amjad Group TitleBest ResponseYou've already chosen the best response.0
formula???
 2 years ago

ali_amjad Group TitleBest ResponseYou've already chosen the best response.0
plzz give the formuale not the final answer
 2 years ago

engr.usman Group TitleBest ResponseYou've already chosen the best response.0
kindly help me on que 1 my value are: The elements in this circuit have the following values: R1=50Ω, R2=50Ω, R3=100Ω, V1=4V, I1=0.0001A and I2=0.001A
 2 years ago

benzo Group TitleBest ResponseYou've already chosen the best response.0
once i get the formula i'll just plug # in
 2 years ago

aakash.kasina Group TitleBest ResponseYou've already chosen the best response.0
thats the answer for Q4
 2 years ago

pauliusn Group TitleBest ResponseYou've already chosen the best response.2
@engr.usman answers 2.9775 1.955 0.0209 0.0211 0.038 0.078 0.000195 0.00195
 2 years ago

VanillyM Group TitleBest ResponseYou've already chosen the best response.0
@pauliusn how did you get these answers? Could you explain/post formula?
 2 years ago

benzo Group TitleBest ResponseYou've already chosen the best response.0
pauliusn...is those the answer for engr question if so what the formula
 2 years ago

aakash.kasina Group TitleBest ResponseYou've already chosen the best response.0
can u tell me the formulae for them @pauliusn
 2 years ago

pauliusn Group TitleBest ResponseYou've already chosen the best response.2
One way is very simple. Just use Circuit Sandbox . There place the your circuit wit own values of components, and then you will get A and B points voltages. And then calculate power is easy. Power on R1 is (V1A)^2/R1; Power on R2 is (AB)^2/R2; If R1=R2  power on these resistors is equal.. Power on R3 is B^2/R3; Power from V1: calculated current from V1*V1 Power from I1: B*I1 Power from I2: B*I2 Something like that.. This is the very easy way. Another way is to use node calculation mode. And then get A and B voltages and then all calculations.
 2 years ago

aakash.kasina Group TitleBest ResponseYou've already chosen the best response.0
thanks dude
 2 years ago
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