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mglebiv
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Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x^2 +16y^2 = 16.
I am totally confused on this one, can someone explain what to do please?
 one year ago
 one year ago
mglebiv Group Title
Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x^2 +16y^2 = 16. I am totally confused on this one, can someone explain what to do please?
 one year ago
 one year ago

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estudier Group TitleBest ResponseYou've already chosen the best response.0
The rectangle area will be 4xy (take x, y as the point in the first quadrant) so A= xy = sqrt(1616y^2)*y and now u have something to differentiate.
 one year ago
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