A community for students.
Here's the question you clicked on:
← 55 members online
 0 viewing
mglebiv
 2 years ago
Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x^2 +16y^2 = 16.
I am totally confused on this one, can someone explain what to do please?
mglebiv
 2 years ago
Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x^2 +16y^2 = 16. I am totally confused on this one, can someone explain what to do please?

This Question is Open

estudier
 2 years ago
Best ResponseYou've already chosen the best response.0The rectangle area will be 4xy (take x, y as the point in the first quadrant) so A= xy = sqrt(1616y^2)*y and now u have something to differentiate.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.