anonymous
  • anonymous
Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x^2 +16y^2 = 16. I am totally confused on this one, can someone explain what to do please?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
The rectangle area will be 4xy (take x, y as the point in the first quadrant) so A= xy = sqrt(16-16y^2)*y and now u have something to differentiate.

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