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whadduptori
Group Title
What is the solution of the system of equations?
somebody please help. can someone show me work?
3x+2y+z= 7
5x+5y+4z=3
3x+2y+3z=1
 one year ago
 one year ago
whadduptori Group Title
What is the solution of the system of equations? somebody please help. can someone show me work? 3x+2y+z= 7 5x+5y+4z=3 3x+2y+3z=1
 one year ago
 one year ago

This Question is Closed

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
how you need to solve it with sustitution method or elimination method ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
I found z by using the equations 1 and 3 and it doesnt tell i need help with x and y
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
ok i see it you can get the value of z using first end 3rd equation so how and how many you have got for z ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
i got z=3 and i know the answer for y is 1 and x is 4 but i dont know how to get them
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
yes z=3 is right sure so than this value of z=3 you can using there in first and second equation so than what will get if you us this value of z there ? what will get for first equation and what for second ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
wait how would set the up?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
3x+2y3=7 5x+5y+4*(3)=3 so can you make the calcule here ?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
courage this is easy
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
how do you figure this out? i feel like an idiot right now
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
in the first equation assun to both sides 3 and will get how many ? so and for second equation multiplie 4 by (3) and will get how many ?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
so you dont wann making the calcules here for ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
12 for the second equation?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
but how will be firstly the first equation ?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
3x+2y=10 do you understand how i have got this result ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
oh okay! you added plus three to the 7? and so the 3 crosses out then?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
yes sure so than how you get the second equation ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
5x+5y12=9
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
equal 3 and not 9
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
okay so what do i do after that?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
so will get 5x+5y12=3 so now add to both sides 12 and will get ????
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
5x+5y=15
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
yes so now there are two equation 3x+2y=10 5x+5y=15 yes ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
okay! got it so far
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
can you solve these system for x and y ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
yeah let me work it out
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
ok now im confused
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
3x+2y=10 5x+5y=15 so first of all how do you see what can you factorizing out in the second equation ?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
why 15 ? and why not just 5 ???
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
yes 5 right so than how will be the second equation ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
im sorry what do you mean?
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
5x+5y=15 i have wrote above that you can factorizing out the 5 from the both sides but i mean that you can divide both sides by 5 and so will get 5x+5y=15 /5 x+y=3 ok ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
okay i see what your ssaying
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
so than now there are 3x+2y=10 x+y=3 can you solve it now ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
what will you solve first the x or y? do you need to get rid of one?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
i got it! i got the answr for y! y=1
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
3x+2y=10 x+y=3  y=3x than this substitute in place of y in the first equation 3x+2(3x)=10 3x+62x=10 x+6=10 x=106 x=4 ok ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
ah thats why i just for x! i get it thank you!
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
so than 4 +y=3 y=34 y=1 so than result that you have got it right ok ?
 one year ago

whadduptori Group TitleBest ResponseYou've already chosen the best response.1
yup! thats what i did, thank you so much
 one year ago

jhonyy9 Group TitleBest ResponseYou've already chosen the best response.1
was my pleasure yw good luck bye
 one year ago
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