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Ashley1593

  • 2 years ago

The crankshaft in a race car goes from rest to 3540rpm in 2.6s. What is the crankshaft's angular acceleration? How many revolutions does it make while reaching 3540rpm?

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  1. 3psilon
    • 2 years ago
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    use \[\omega = \omega _o + \alpha t\] \[\omega_o= 0 \] since it starts from rest. so \[\omega = \alpha t\] solve for alpha\[\alpha=\frac{ \omega }{ t }\] Now just plug in and solve. Also I'm assuming your answer should be in radians/sec? \[\frac{ 3540rev/m }{ 2.6\sec } * \frac{ 2\pi }{ 1 rev }*\frac{ 1 \min }{60 \sec } = 142.58 rad/s^{2}\]

  2. 3psilon
    • 2 years ago
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    For the second part use the angular displacement formula \[\Delta \theta = \omega _o +\frac{ 1 }{ 2 } \alpha t^{2}\] and just plug in (note it starts from rest so omega initial = 0)

  3. Omniscient1
    • 2 years ago
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    Nice @3psilon

  4. 3psilon
    • 2 years ago
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    Make sense @Ashley1593

  5. 3psilon
    • 2 years ago
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    ?

  6. Ashley1593
    • 2 years ago
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    yes thank you

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